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4 years ago

Is 0.62 a rational number?

Mathematics

2 answers:

dimaraw [331]4 years ago

7 0

A rational number is any number that can be written as a ratio of two integers.

0.62 fits the bill, as it can be written as the ratio 62/100 (or simplified to the ratio 31/50)

Bingel [31]4 years ago

4 0

Yes man yes man yes yes

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The equation for the line of best fit is f(x) â‰ 1. 8x â’ 5. 4 for the set of values in the table. A 2-column table with 7 rows.

AleksandrR [38]

The equation for the line of best fit, the good approximation for x when f(x) = 30 is 20.

Given that

The equation for the line of best fit is f(x) = 1.8x − 5.4 for the set of values in the table.

A 2-column table with 7 rows.

The first column is labeled x with entries 4, 5, 6, 6, 8, 9, 10.

The second column is labeled f(x) with entries 5, 2, 5, 6, 8, 7, 18.

We have to determine

Using the equation for the line of best fit, what is a good approximation for x when f(x) = 30?

According to the question

The quadratic regression equation can be expressed as;

$\rm f(x) = 1.8x - 5.4$

Then,

The approximation for x when f(x) = 30 is,

$\rm f(x) = 1.8x - 5.4\\\\\rm 30= 1.8x - 5.4 \\\\ 1.8x= 30+5.4\\\\1.8x=35.4\\\\x = \dfrac{35.4}{1.4}\\\\x=19.67\\\\x=20 \ approx$

Hence, the equation for the line of best fit, the good approximation for x when f(x) = 30 is 20.

To know more about the Quadratic equation click the link given below.

brainly.com/question/26164308

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3 years ago

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Answer:

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Step-by-step explanation:

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A) Find a recurrence relation for the number of bit strings of length n that contain a pair of consecutive 0s.

Fed [463]

Answer:

A) $a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}$

B) $a_{0} = a_{1} = 0$

C) for n = 2

$a_{2}$ = 1

for n = 3

$a_{3}$ = 3

for n = 4

$a_{4}$ = 8

for n = 5

$a_{5}$ = 19

Step-by-step explanation:

A) A recurrence relation for the number of bit strings of length n that contain a pair of consecutive Os can be represented below

if a string (n ) ends with 00 for n-2 positions there are a pair of consecutive Os therefore there will be : $2^{n-2}$ strings

therefore for n ≥ 2

The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os

$a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}$

b ) The initial conditions

The initial conditions are : $a_{0} = a_{1} = 0$

C) The number of bit strings of length seven containing two consecutive 0s

here we apply the re occurrence relation and the initial conditions

$a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}$

for n = 2

$a_{2}$ = 1

for n = 3

$a_{3}$ = 3

for n = 4

$a_{4}$ = 8

for n = 5

$a_{5}$ = 19

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3 years ago