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antoniya [11.8K]
3 years ago
10

If al|b, mZ1 = 10x + 2 and mZ4 = 5x + 13 , find mZ1 and m<2

Mathematics
1 answer:
morpeh [17]3 years ago
5 0
Um un um i’m i’m in i’m i’m um um u me m um i’m in ...21
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Subtract (In picture)
Sonbull [250]

--First we have to simplfy

\frac{2x-8}{x^2-x-12} -\frac{x-3}{x(x+1)}

\frac{2(x-4)}{(x-4)(x+3)} - \frac{x-3}{x(x+1)}

--Cancel common factors

\frac{2}{(x+3)} -\frac{x-3}{x(x+1)}

--Here remember never cancel factors in a subtraction or addition problem

--Now Multiply each side until both denominators are equal to each other

\frac{2[x(x+1)]}{x(x+3)(x+1)} -\frac{(x-3)(x+3)}{x(x+3)(x+1)}

--Simplify

\frac{2x^2+2x}{x(x+1)(x+3)} - \frac{x^2-9}{x(x+1)(x+3)}

--Now that the denominators are the same: subtract!

\frac{2x^2+2x-(x^2-9)}{x(x+1)(x+3)}

\frac{2x^2-x^2+2x+9}{x(x+1)(x+3)}

--And LAST STEP! ......Simplify More.... To get your answer

\frac{x^2+2x+9}{x(x+1)(x+3)}


6 0
3 years ago
Given that D is he midpoint of AB and K is the midpoint of BC, which statement must be true?
Reil [10]
I can't understand your question do you have any number there?
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2 years ago
The square root of x^16y^2
ASHA 777 [7]

\bf \sqrt{x^{16}y^2}\implies \sqrt[2]{x^{8\cdot 2}y^2}\implies \sqrt[2]{(x^8)^2y^2}\implies x^8y

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3 years ago
Help 35 points, this is algebra 1 on system of equations and inequalities
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Answer:

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Given the function y=log3(x+2)-2. List the transformations
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Answer:

Exponential transformation.

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y = log_3 (x + 3) - 2

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Adding 2 to both sides

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2 years ago
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