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Sonbull [250]
4 years ago
11

Why is no one helping or answering ANY of my questions asked so far? :( I thought it said questions are normally answered with-i

n 10 minutes...
Mathematics
1 answer:
vodka [1.7K]4 years ago
3 0
Questions are USUALLY answered within 10 minutes.

Therefore, you're questions might be complicated, hard, or incomplete.

Actual people are answering these questions, so obviously the easier questions get answered first.
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A childs pool contains 17500 millileters. how many liters are in the pool
Aleks04 [339]

Answer:

17.5 litres

Step-by-step explanation:

1000 mililitres = 1 litre

17500 mililitres = 17.5 littes

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3 years ago
Write the decimal for 1/8 Explain why this decimal is called terminating decimal
alexandr1967 [171]

Answer:

0.125

This is a terminating decimal because after a finite amount of digits, the decimal comes to an end. The decimal does not continue for an infinite amount of digits.

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3 years ago
The shape of a normal distribution is
Tatiana [17]

Symmetry means that one half of the distribution is a mirror image of the other half. For example, the normal distribution is a symmetric distribution with no skew. The tails are exactly the same

its D

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3 years ago
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What is the area of a rhombus with diagonals measuring 8.6 in and 15.3 in.
BigorU [14]
The area of the rhombus is 65.79
7 0
3 years ago
Ocean sunfish are well known for rapidly gaining a lot of weight on a diet based on jellyfish. The relationship between the elap
Maksim231197 [3]

Answer:

Every day, the mass of the sunfish is multiplied by a factor of <u>[ln(1.34)/6]. </u>

<u></u>

Step-by-step explanation:

You have the following function:

M(t)=(1.34)^{\frac{t}{6}+4}

To know what is the factor that multiplies the mass of the sunfish each day, you derivative the function M(t):

\frac{dM(t)}{dt}=(1.34)^{\frac{t}{6}+4}(\frac{1}{6})ln(1.34)\\\\\frac{dM(t)}{dt}=\frac{ln(1.34)}{6}[(1.43)^{\frac{t}{6}+4}]\\\\\frac{dM(t)}{dt}=\frac{ln(1.34)}{6}M(t)  (1)

where you have used the following general derivative:

g(t)=a^{f(t)}\\g'(t)=a^{f(t)}f'(t)ln(a)

The derivative give you the increase in the mass per day (because t is days). By the expression (1) you can conclude that each day the mass increase a factor of [ln(1.34)/6].

Every day, the mass of the sunfish is multiplied by a factor of <u>[ln(1.34)/6]. </u>

8 0
3 years ago
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