The image is decomposed as follows: H1 and H2. Where original graph is Hx.
<h3>Are the images (attached) valid decompositions of the original graph?</h3>
- Yes, they are because, H1 and H1 are both sub-graphs of Hx; also
- H1 ∪ H2 = Hx
- They have no edges in common.
Hence, {H1 , H2} are valid decomposition of G.
<h3>What is a Graph Decomposition?</h3>
A decomposition of a graph Hx is a set of edge-disjoints sub graphs of H, H1, H2, ......Hn, such that UHi = Hx
See the attached for the Image Hx - Pre decomposed and the image after the graph decomposition.
Learn more about decomposition:
brainly.com/question/27883280
#SPJ1
Answer:
Step-by-step explanation:
<h3><u>Question 6</u></h3>
To find the greatest common factor (GCF), first list the prime factors of each number:
- 42 = 2 × 3 × 7
- 60 = 2 × 2 × 3 × 5
42 and 60 share one 2 and one 3 in common.
Multiply them together to get the GCF: 2 × 3 = 6.
Therefore, 6 is the GCF of 42 and 60.
Divide the numerator and the denominator by the found GCF:
<h3><u>Question 7</u></h3>
To find the greatest common factor (GCF), first list the prime factors of each number:
- 80 = 2 × 2 × 2 × 2 × 5
- 272 = 2 × 2 × 2 × 2 × 17
80 and 272 share four 2s in common.
Multiply them together to get the GCF: 2 × 2 × 2 × 2 = 16.
Therefore, 16 is the GCF of 80 and 272.
Divide the numerator and the denominator by the found GCF:
Negative exponents work like this:
So, in order to evaluate a negative exponent, you simply have to invert the base, and then raise to the positive equivalent of the exponent.
As an example, here are the first three exercises:
You can work out the rest applying this logic.
Answer:
1st option 9/4
Step-by-step explanation: Searched up the problem on brainly and this was the answer. Hope that helps
Night 1-
Wren 12
Jenni 4
Night 2-
Wren 16
Jenni 9
Night 3-
Wren 20
Jenni 14
Night 4-
Wren 24
Jenni 19
Night 5-
Wren 28
Jenni 24
Night 6-
Wren 32
Jenni 29
Night 7-
Wren 36
Jenni 34
Night 8-
Wren 40
Jenni 39
Night 9-
Wren 44
Jenni 44
It would be 9 nights.
Graph using (x) and (y), Wren being (x) and Jenni being (y)
