3 years ago

I'm confused on this help ??

1 answer:

7 0

(2^8 x 3^-5 x 6^0) x [(3^-2/2^3) x 2^28] = x
(256 x .004 x 1) x [(.111/8) x 268,435,456] = x
(1.024 x 1) x .(0138 x 268,435,456) = x
1.024 x (.0138 x 268,435,456) = x
1.024 x 3,704,409.2928 = x
3,793,315.1158272 = x
Correct me if I am wrong. :)

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Use the parabola tool to graph the quadratic function f(x)=−12x2+7. Graph the parabola by first plotting its vertex and then plo

Fudgin [204]

First we find the vertex of parabola $f(x)=-12 x^{2} +7$

The vertex of parabola is $( \frac{-b}{2a},f( \frac{-b}{2a}))$
Here,
b = coefficient of x term
a = coefficient of x² term

For given parabola, b = 0 , a = -12

So,
$\frac{-b}{2a}= \frac{0}{-24} =0$

And,

$f( \frac{-b}{2a} )=f(0) = -12(0)+7=7$

Thus the vertex of parabola is (0, 7)

To find another point on parabola, substitute x by 1.

$f(1)=-12( 1^{2}) +7=-12+7=-5$

So the second point on parabola is (1,-5)

The plot of parabola is shown in image below: