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inn [45]
3 years ago
13

I'm confused on this help ??

Mathematics
1 answer:
nika2105 [10]3 years ago
7 0
(2^8 x 3^-5 x 6^0) x [(3^-2/2^3) x 2^28] = x
(256 x .004 x 1) x [(.111/8) x 268,435,456] = x
(1.024 x 1) x .(0138 x 268,435,456) = x
1.024 x (.0138 x 268,435,456) = x
1.024 x 3,704,409.2928 = x
3,793,315.1158272 = x
Correct me if I am wrong. :)
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Need help please, does any one know how to do this​
ziro4ka [17]

Answer:

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Step-by-step explanation:

There are a few ways you can write the equivalent of this.

1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...

  (-u+6)/(u+2)

Or, you can rearrange the terms so the leading coefficient is positive:

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2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.

  -(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)

or

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Of course, anywhere along the chain of equal signs the expressions are equivalent.

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3) You can separate the numerator terms, expressing each over the denominator:

(-u +6)/(u+2) = -u/(u+2) +6/(u+2)

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4) You can also multiply numerator and denominator by some constant, say 3:

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You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:

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7 0
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Sladkaya [172]
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8 0
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2 years ago
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lisabon 2012 [21]
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7 0
3 years ago
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