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3 years ago

Using the quadratic formula solve 2x^2+10x+3

Mathematics

1 answer:

kaheart [24]3 years ago

3 0

Pretty long one but it’s -5+/- sqrt(19) all over 2. Hope this helps!!!

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liza's friend marie bought her a dress for 250 euros in france. liza wants to pay marie for it in u.s. dollars. if the foreign e

Rudik [331]

1/ 0.6 = x / 250..1 dollar to 0.6 euros = x dollars to 250 euros
cross multiply
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4 years ago

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Dmitry [639]

(x-3)^2=10
I hope this helps you.

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3 years ago

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Tamiku [17]

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3 years ago

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In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th

olya-2409 [2.1K]

Answer:

$\frac{BE}{EC} =\frac{1}{3}$

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

$\frac{BK}{CK} =\frac{1}{4}$

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK and Δ EBK are similar

so we have

$\frac{AD}{BE} =\frac{DK}{BK}$

$\frac{AD}{BE} =\frac{4}{1}$

$\frac{BC}{BE}=\frac{4}{1}$ ( ABCD is parallelogram so AD=BC)

$\frac{BE+EC}{BE}=\frac{4}{1}$ ( BC= BE+EC)

$\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}$

$1+\frac{EC}{BE}=4$

$\frac{EC}{BE}=3$ ( subtracting 1 from both side )

$\frac{EC}{BE}=\frac{3}{1}$

taking reciprocal both side

$\frac{BE}{EC} =\frac{1}{3}$

8 0

4 years ago

Ele:

lana66690 [7]

Answer:

The pattern is that, every time a 9 is added. This pattern continuous forever.

Step-by-step explanation:

9 X 1 = 9

9 X 2 = 18 (9+9)

9 X 3 = 27 (9+9+9)

Etc.

5 0

3 years ago

Using the quadratic formula solve 2x^2+10x+3​

Using the quadratic formula solve 2x^2+10x+3