Answer: Tt is unlikely to have change in the sample mean score is less than 10 points .
Step-by-step explanation:
Given : Mean :
Standard deviation :
Sample size : n= 100
We assume that the change in students scores are normally distributed.
Let X be the random variable that represents the change in students scores .
Z score :
For x = 10
By using the standard normal distribution table , the probability that the change in the sample mean score is less than 10 points :-
Since the calculated probability is less than 0.5.
So , we say that it is unlikely to have change in the sample mean score is less than 10 points .
First, you would turn 2 1/9 into an improper fraction. 2 1/9 is now turned into 19/9. Now, you need to find a common denominator between 19/9 and 5/6. The least common denominator, which is the smallest number that both denominators can multiply to, is 18. 19/9 is turned into 38/18 (which is still 19/9 when simplified). 5/6 is turned into 15/18. Now, since both 38/18 and 15/18 have a common denominator, we can write the fraction like (38-15)/18. 38-15 is 23, so your answer is 23/18. When simplified, 23/18 becomes 1 5/18.
Answer:
sinΘ =1
Step-by-step explanation:
cosΘ × cosΘ/sinΘ+ sinΘ = sinΘ
cos^2 Θ/sinΘ +sinΘ =sinΘ
cos^2Θ+ sin^2Θ /sin Θ = sinΘ
1/sinΘ =sinΘ
<span>-9 -10[7x -3(3 + 10x)]
= -9 - 10(7x - 9 - 30x)
= -9 - 10( -23x - 9)
= -9 + 230x + 90
= 230x + 81
Answer: </span>230x + 81<span>
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