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3 years ago

How does acceleration affect speed and velocity

1 answer:

5 0

Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.

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Describe how humans’ actions and natural processes have modified coastal regions in Louisiana and other locations

il63 [147K]

Coastal erosion has depleted a large portion of South Louisiana's wetlands along the coastline in swamps and marshes mainly due to storm surges. But other factors also contributed to this erosion. Canals and waterways dug through the marshes and swamps for the oil industry is one factor. Man-made levees erected to provide protection to residents living adjacent to the river is another major cause. Large scale logging especially in the early 1900's also damaged the wetlands.

3 0

3 years ago

What best describes the volcanic process of magma with dissolved water vapor and other gases as it nears the Earth surface?

Assoli18 [71]

Answer:

Pressure on the molten rock lessens and the gases dissolved in rock can bubble and expand rapidly causing violent eruptions.

Explanation:

that's just how it works lol. hope this helps :]

6 0

3 years ago

3500 as a power of 10

Luba_88 [7]

Answer: 3.5 × 10^3

Explanation:

8 0

3 years ago

A stationary horn emits a sound with a frequency of 228 Hz. A car is moving toward the horn on a straight road with constant spe

stiks02 [169]

Answer: 26.84 m/s

Explanation:

Given

Original frequency of the horn $f_o=228\ Hz$

Apparent frequency $f'=246\ Hz$

Speed of sound is $V=340\ m/s$

Doppler frequency is

$\Rightarrow f'=f_o\left(\dfrac{v+v_o}{v-v_s}\right)$

Where,

$v_o=\text{Velocity of the observer}\\v_s=\text{Velocity of the source}$

Insert values

$\Rightarrow 246=228\left[\dfrac{340+v_o}{340-0}\right]\\\\\Rightarrow 366.84=340+v_o\\\Rightarrow v_o=26.8\ m/s$

Thus, the speed of the car is $26.84\ m/s$

4 0

3 years ago

What is the magnitude of the electrostatic force

ozzi

The electron charge is called the Elementary Charge, given by:

$e=1.6*10^{-19}$

The Eletrostatic Force bewteen two changes is giver by Coulomb Law:

$F= \frac{Qqk}{d^2}$

Substituing the unknowns, we have:

$F= \frac{(1.6*10^{-19})^2}{(10^{-8})^2} \\ F=(1.6*10^{-11})^2 \\ \boxed {F=2.56*10^{-22}N}$

If you notice any mistake in my english, please let me know, because i am not native.

5 0

3 years ago

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