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dexar [7]
3 years ago
5

A lamp has a power of 120 W and is left on for 24 hours . A television has a power of 350 W and is left on for three hours . com

pares the energy used by these devices
Physics
2 answers:
boyakko [2]3 years ago
8 0

Answer:

2.74

Explanation:

Power of lamp, PL = 120 W, t = 24 hours

Power of TV, PT = 350 W, t = 3 hours

Energy consumed by a lamp, EL = Power x time = 120 x 24 = 2880 W h

Energy consumed by a TV, ET = power x time = 350 x 3 = 1050 W h

EL / ET = 2880 / 1050 = 2.74

Paladinen [302]3 years ago
7 0
This is a power problem which requires the rearranging of a formula. The lamps energy used is 5 N, and the TV’s usage is 116.7 N (rounded from 116.6666repeating). Here my work:
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Chemical name and a common name for NaOH​
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A 0.07-kg lead bullet traveling 258 m/s strikes an armor plate and comes to a stop. If all of the bullet's energy is converted t
Lubov Fominskaja [6]

Answer:

temperature change is 262.06°K

Explanation:

given data

mass = 0.07 kg

velocity = 258 m/s

to find out

what is its temperature change

solution

we know here

heat change Q is is equal to kinetic energy that is

KE = 0.5 × m× v²   ...........1

here m is mass and v is velocity

KE = 0.5 × 0.07 × 258²

KE = 2329.74 J

and we know

Q = mC∆t     .................2

here m is mass and ∆t is change in temperature and C is 127J/kg-K

so put here all value

2329.74 = 0.07 × 127 × ∆t

∆t = 262.06

so temperature change is 262.06°K

7 0
3 years ago
How much force would you need to accelerate a 528 kg motorcycle at 3 m/s2
mart [117]

Answer:

<h2>1584 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 528 × 3

We have the final answer as

<h3>1584 N</h3>

Hope this helps you

4 0
3 years ago
A cat walks along a plank with mass M= 7.00 kg. The plank is supported by two sawhorses. The center of mass of the plank is a di
solong [7]

Answer:

Before the plank will tip cat will walk 1.652 m

Explanation:

Mass of the cat along with plank m_1=7kg

Center of mass of the plank d_1=0.850m

Mass of cat m_2=3.6kg

We have to find how far right of sawhorse B.

Plank will tip when weight of the cat about B is greater than the torque by the weight of the plank.

Balancing the the torque

m_1gd_1=m_1gd_2

7\times 9.8\times 0.850=3.6\times 9.8\times d_2

d_2=1.652m

5 0
4 years ago
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