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3 years ago

13

A certain lightning bolt moves 40.0 C of charge. How many fundamental units of charge |qe| is this?

2 answers:

Harman [31]3 years ago

7 0

Answer:

There are $25\times10^{19}$ unit of charge this.

Explanation:

Given that,

Charge =40.0 C

We know that,

The unit of fundamental charge is

$q= 1.6\times10^{-19}\ C$

1 C of charge = $\dfrac{\text{1 unit of fundamental charge}}{1.6\times10^{-19}}$

40.0 C of charge = $\dfrac{\text{40 unit of fundamental charge}}{1.6\times10^{-19}}$

$\text{40.0 C of charge}=\dfrac{40}{1.6\times10^{-19}}$

$\text{40.0 C of charge}=25\times10^{19}$

Hence, There are $25\times10^{19}$ unit of charge this.

Simora [160]3 years ago

4 0

Answer:

$25\times 10^{19}$ units

Explanation:

We are given that

Charge=q=40.0 C

We have to find the number of fundamental units of charge .

We know that

1 e-= $1.6\times 10^{-19}$ C

We know that

$q=ne$

Using the formula

$40=n\times 1.6\times 10^{-19}$

$n=\frac{40}{1.6\times 10^{-19}}$

$n=25\times 10^{19}$ units

Hence, the fundamental units of charge= $25\times 10^{19}$ units

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Oliga [24]

Answer:

Q = 116.8 J

Explanation:

Here given that the temperature of 1 L hydrogen is increased by 90 degree C at constant pressure condition.

So here we will have

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here we know that

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now we have

$Q = (0.0446)(\frac{7}{2}R)(90)$

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3 years ago

A sample of aluminum has a mass of 4.86 grams and a volume of 1.8 cubic centimeters. What is the density of aluminum rounded to

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Answer:

3g/cm³

Explanation:

2.7

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3 years ago

Given that the internal energy of water at 28 bar pressure is 988 kJ kg–1 and that the specific volume of water at this pressure

klasskru [66]

Answer:

1184 kJ/kg

Explanation:

Given:

water pressure P= 28 bar

internal energy U= 988 kJ/kg

specific volume of water v= 0.121×10^-2 m^3/kg

Now from steam table at 28 bar pressure we can write

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therefore at saturated liquid we have specific enthalpy at 55 bar pressure.

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3 years ago

An oscillator consists of a block attached to a spring (k = 500 N/m). At some time t, the position (measured from the system's e

Alex_Xolod [135]

Answer:

a) $\omega = 10.407\,\frac{rad}{s}$ , b) $m = 4.617\,kg$ , c) $A = 1.355\,m$

Explanation:

a) The system have a simple armonic motion, whose position function is:

$x(t) = A\cdot \cos (\omega\cdot t + \phi)$

The velocity function is determined by deriving the position function in terms of time:

$v(t) = -\omega \cdot A \cdot \sin(\omega\cdot t + \phi)$

The acceleration function is found by deriving again:

$a(t) = -\omega^{2} \cdot A \cdot \cos (\omega\cdot t + \phi)$

Let assume that $t = 0\,s$ . The following nonlinear system is built:

$A\cdot \cos \phi = 0.660\,m$

$-\omega \cdot A \cdot \sin \phi = -12.3\,\frac{m}{s}$

$-\omega^{2}\cdot A \cdot \sin \phi = -128\,\frac{m}{s^{2}}$

System can be reduced by divinding the second and third expressions by the first expression:

$\omega \cdot \tan \phi = 18.636\,\frac{1}{s}$

$\omega^{2}\cdot \tan \phi = 193.94\,\frac{1}{s^{2}}$

Now, the last expression is divided by the first one:

$\omega = 10.407\,\frac{rad}{s}$

b) The mass of the block is:

$m = \frac{k}{\omega^{2}}$

$m = \frac{500\,\frac{N}{m} }{(10.407\,\frac{rad}{s})^{2} }$

$m = 4.617\,kg$

c) The phase angle is:

$\phi = \tan^{-1} \left(\frac{18.636\,\frac{1}{s} }{\omega} \right)$

$\phi \approx 0.338\pi$

The amplitude is:

$A = \frac{0.660\,m}{\cos 0.338\pi}$

$A = 1.355\,m$

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3 years ago

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1 A standard transformer has a rating of 60 kVA. The primary and secondary voltages are rated respectively at 600 V and 120 V. (

Viefleur [7K]

Answer:

The rated current for the 600V side is I = 100 A and the rated current for the 120 V side is 500 A.

Explanation:

For standard transformers they step up or down the level of voltage while maintaning the power output (ideally). So the same power output should be seen on both sides, since the equation for apparent power is P = V*I we can solve for I on both sides and find the rated current. So we have:

600 V side:

P = V*I

I = P/V = (60*10^3)/600 = 100 A

120 V side:

P = V*I = (60*10^3)/120 = 500 A

6 0

3 years ago

Read 2 more answers