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Mnenie [13.5K]
3 years ago
13

A certain lightning bolt moves 40.0 C of charge. How many fundamental units of charge |qe| is this?

Physics
2 answers:
Harman [31]3 years ago
7 0

Answer:

There are 25\times10^{19} unit of charge this.

Explanation:

Given that,

Charge =40.0 C

We know that,

The unit of fundamental charge  is

q= 1.6\times10^{-19}\ C

1 C of charge =\dfrac{\text{1 unit of fundamental charge}}{1.6\times10^{-19}}

40.0 C of charge = \dfrac{\text{40 unit of fundamental charge}}{1.6\times10^{-19}}

\text{40.0 C of charge}=\dfrac{40}{1.6\times10^{-19}}

\text{40.0 C of charge}=25\times10^{19}

Hence, There are 25\times10^{19} unit of charge this.

Simora [160]3 years ago
4 0

Answer:

25\times 10^{19} units

Explanation:

We are given that

Charge=q=40.0 C

We have to find the number of fundamental units of charge .

We know that

1 e-=1.6\times 10^{-19}C

We know that

q=ne

Using the formula

40=n\times 1.6\times 10^{-19}

n=\frac{40}{1.6\times 10^{-19}}

n=25\times 10^{19} units

Hence, the fundamental units of charge=25\times 10^{19} units

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b.Now when the package stick together there momentum is conserved.

Using law of conservation of momentum.

m_1V_1(i) = (m_1+m_2)V_f where V_1{i} =7.668\ ms^-1.

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As here V_{f}=-2.56\ ms^-1 we can use that if both are moving in right ward with 2.56 then there is a  -2.56 velocity when they have to move leftward.

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