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4 years ago

Explain how a battery in a circuit is similar to a water pump.

1 answer:

5 0

<span>A battery creates a potential difference, or voltage, which is really just storing electrical potential energy just as a pump would by moving water up against gravity, thereby storing gravitational potential energy. To complete the analogy, as current flows through the circuit, this potential energy is released and can be used by the components in the circuit. This is the same as water falling back down and turning some wheel or turbine and converting its gravitational potential energy into mechanical energy.</span>

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An aluminum wire with a diameter of 0.115 mm has a uniform electric field of 0.235 V/m imposed along its entire length. The temp

tekilochka [14]

Answer with Explanation:

We are given that

Diameter of coil=d=0.115mm

Radius, r= $\frac{d}{2}=\frac{0.115}{2}=0.0575mm=0.0575\times 10^{-3} m$

Using $1mm=10^{-3} m$

Electric field=E=0.235V/m

T=55 degree C

$T_0=20^{\circ} C$

$\rho_0=2.82\times 10^{-8}\Omega m$

$\alpha=3.9\times 10^{-3}/C$

(a).We know that

$\rho=\rho_0(1+\alpha(T-T_0))$

Substitute the values

$\rho=2.82\times 10^{-8}(1+3.9\times 10^{-3}(55-20))$

$\rho=3.2\times 10^{-8}\Omega m$

(b).Current density, $J=\frac{E}{\rho}$

Using the formula

$J=\frac{0.235}{3.2\times 10^{-8}}=7.3\times 10^6A/m^2$

c.Total current,I=JA

Where $A=\pi r^2$

$\pi=3.14$

Using the formula

$I=7.3\times 10^6\times 3.14\times (0.0575\times 10^{-3})^2$

I=0.076A

d.Length of wire=l=2m

$V=El$

Substitute the values

$V=0.235\times 2=0.47 V$

5 0

3 years ago

Consider two objects of the same mass. If a force of 100N acts on the first for a duration of 1s and on the other for a duration

kompoz [17]

So velocity=displacement/time and force=mass*acceleration. Both objects have the same acceleration because the amount of time doesn’t play a role in the equation. Momentum equation is p=mv so only the mass and overall velocity matter. Therefore, the answer is c because time is not a variable

6 0

3 years ago

Read 2 more answers

Assume that a machine puts out 8000 joules of work when the user puts in 10,000 joules of work. What is the efficiency of the ma

-BARSIC- [3]

Answer:

80 Percent

Explanation:

E=energy output/energy input×100

E=8000/10000×100

E=0.8×100

E=80 percent.