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Hitman42 [59]
3 years ago
6

A paper clip is dropped from the top of a 144‐ft tower, with an initial velocity of 16 ft/sec. Its position function is s(t) = −

16t2 + 144. What is its velocity in ft/sec when it hits the ground?
-96
-64
-32
0

Mathematics
1 answer:
BabaBlast [244]3 years ago
7 0
\bf s(t)=-16t^2+144\implies \stackrel{velocity}{\cfrac{ds}{dt}}=-32t

when does it hit the ground?  check the picture below.

\bf 0=-16t^2+144\implies 16t^2=144\implies t^2=\cfrac{144}{16}\implies t^2=9
\\\\\\
t=\sqrt{9}\implies t=3

at that moment, the velocity is -32(3).

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Answer:

angle B: 39

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Step-by-step explanation:

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Step-by-step explanation:

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