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2 years ago

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Question: determine all solutions to the diophantine equation 3x + 7y = 4

1 answer:

yKpoI14uk [10]2 years ago

3 0

The difference between the coefficients 7 and 3 is 4, so one solution is
y = 1, x = -1.
Then the remaining solutions will be of the form
x = -7n-1
y = 3n+1
for some integer n.

_____
Some of the solutions are (for n=0, -1, -2, 1, 2)
(x, y) = (-1, 1), (6, -2), (13, -5), (-8, 4), (-15, 7)

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PLEASE HELP! Solve for q(x) and r(x). (4x^3-3x^2+5x-7)/(x-2) = q(x)+ r(x)/(x-2)

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2 years ago

What is the quotient and remainder of (4x^3-3x^2+x+7)/(x-2)

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2 years ago

Suppose f varies directly as g, and f varies inversely as h. Find g when f = 10 and h = –12, if g = 56 when h = –2 and f = –7. R

kow [346]

Answer:

-480

Step-by-step explanation:

If f varies directly as g, and inversely as h, then we can write the variation equation:

$f=\frac{kg}{h}$ , where k is the constant of variation.

If g=56 when h=-2 and f=-7, then we substitute these values into the formula to find the value of k.

$-7=\frac{k(56)}{-2}$

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$f=\frac{g}{4h}$

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