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oee [108]
3 years ago
7

How many solutions does the system below have?

Mathematics
1 answer:
lapo4ka [179]3 years ago
4 0
Answer: 1 solution

An augmented matrix for the system is
[2,6,12;1,1,2] where we will call the first two columns A and the third b. A is linearly independent since it is row equivalent to the identity matrix, which tells us that for any b there will be a unique solution (x,y).
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Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
3 years ago
What can the intersection of a regular octagon and line segment be?
noname [10]

Answer:

See below

Step-by-step explanation:

Intersection of a regular octagon and a line segment can result in:

  • Triangle (ABC as example)
  • Quadrilateral (ABCD as example)
  • Pentagon (ABCDE as example)
  • Hexagon (ABCDEF as example)
  • Heptagon (ABCDEFG as example)

Refer to attached

8 0
3 years ago
Rewrite the equation in logarithmic form: 4^3 = 64
storchak [24]
4^3 = 64

log4 64 = 3

The exponent always comes to the other side.
8 0
3 years ago
What is the value of x?
UkoKoshka [18]

Answer:

x = 3

Step-by-step explanation:

3/2.25 = 4/x                 Cross multiply

3x = 2.25 * 4                Combine the right

3x = 9                           Divide by 3

3x/3 = 9/3

x = 3

7 0
3 years ago
State domain and range for following graph
Zarrin [17]

Answer:

All Real Numbers or (-∞,∞) for both domain and range

Step-by-step explanation:

The line is growing infinitely in both directions, so it will end up reaching every x and y value in both directions

3 0
3 years ago
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