quadratic equations can be soled by 3 methods
factorization
completing square
quadratic formula
but factorization is the simplest
Answer : 96
x – y = 16 --------> equation 1
1/8 x + 1/2 y = 52
x is the higher grade and y is the lower grade
We solve the first equation for y
x - y = 16
-y = 16 -x ( divide each term by -1)
y = -16 + x
Now substitute y in second equation
1/8 x + 1/2 ( -16 + x ) = 52
1/8x - 8 + 1/2 x = 52
1/8x + 1/2x - 8 = 52
Take common denominator to combine fractions
1/8x + 4/8x -8 = 52
5/8x - 8 = 52
Add 8 on both sides
5/8x = 60
Multiply both sides by 8/5
x = 96
We know x is the higher grade
96 is the higher grade of Jose’s two tests.
Answer:
a) ∝A ∈ W
so by subspace, W is subspace of 3 × 3 matrix
b) therefore Basis of W is
={
}
Step-by-step explanation:
Given the data in the question;
W = { A| Air Skew symmetric matrix}
= {A | A = -A^T }
A ; O⁻ = -O⁻^T O⁻ : Zero mstrix
O⁻ ∈ W
now let A, B ∈ W
A = -A^T B = -B^T
(A+B)^T = A^T + B^T
= -A - B
- ( A + B )
⇒ A + B = -( A + B)^T
∴ A + B ∈ W.
∝ ∈ | R
(∝.A)^T = ∝A^T
= ∝( -A)
= -( ∝A)
(∝A) = -( ∝A)^T
∴ ∝A ∈ W
so by subspace, W is subspace of 3 × 3 matrix
A ∈ W
A = -AT
A = ![\left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Do%26a%26b%5C%5C-a%26o%26c%5C%5C-b%26-c%260%5Cend%7Barray%7D%5Cright%5D)
=
![+c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]](https://tex.z-dn.net/?f=%2Bc%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%260%5C%5C0%260%261%5C%5C0%26-1%260%5Cend%7Barray%7D%5Cright%5D)
therefore Basis of W is
={
}
Answer:
True
Step-by-step explanation:
4n - 9 + 3n + 5 + n = 68
combine like terms
8n - 4 = 68
addition property of equations
8n = 72
division property of equality
n = 9
SIDES:
n = 9
3n + 5 = 32
[ 3(9) + 5 = 32 ]
4n - 9 = 27
[ 4(9) - 9 = 27 ]