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Shalnov [3]
3 years ago
15

Find the distance between the two points. (2, 5) and (–1, –5)

Mathematics
2 answers:
Ad libitum [116K]3 years ago
6 0
<span>√109</span>≈<span>10.44030650 <--- Answer

</span>Distance=<span>√<span><span><span>(<span>x2</span>−<span>x1</span>)</span>2</span>+<span><span>(<span>y2</span>−<span>y1</span>)</span><span>2

</span></span></span></span>√<span><span><span>(<span>(−1)</span>−<span>(2)</span>)</span>2</span>+<span><span>(<span>(−5)</span>−<span>(5)</span>)</span><span>2 

That check sign is the square root, since they wouldnt let me put it in...</span></span></span>
mario62 [17]3 years ago
4 0
\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ 2 &,& 5~) &#10;%  (c,d)&#10;&&(~ -1 &,& -5~)&#10;\end{array}&#10;\\\\\\&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;d=\sqrt{(-1-2)^2+(-5-5)^2}&#10;\\\\\\&#10;d=\sqrt{(-3)^2+(-10)^2}\implies  d=\sqrt{109}
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What is the simple way of solving quadratic equation ​
aleksandrvk [35]

quadratic equations can be soled by 3 methods

factorization

completing square

quadratic formula

but factorization is the simplest

4 0
3 years ago
Jose asks his friends to guess the higher of two grades he received on his math tests. He gives them two hints. The difference o
tatyana61 [14]

Answer : 96

x – y = 16 --------> equation 1

1/8 x + 1/2 y = 52

x is the higher grade and y is the lower grade

We solve the first equation for y

x - y = 16

-y = 16 -x ( divide each term by -1)

y = -16 + x

Now substitute y in second equation

1/8 x + 1/2 ( -16 + x ) = 52

1/8x - 8 + 1/2 x = 52

1/8x + 1/2x - 8 = 52

Take common denominator to combine fractions

1/8x + 4/8x -8 = 52

5/8x - 8 = 52

Add 8 on both sides

5/8x = 60

Multiply both sides by 8/5

x = 96

We know x is the higher grade

96 is the higher grade of Jose’s two tests.

8 0
3 years ago
skew-symmetric 3 x 3 matrices form as subspace of all 3 x 3 matrices and find a basis for this subspace.
Neporo4naja [7]

Answer:

a) ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

b) therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

Step-by-step explanation:

Given the data in the question;

W = { A| Air Skew symmetric matrix}

= {A | A = -A^T }

A ; O⁻ = -O⁻^T        O⁻ : Zero mstrix

O⁻ ∈ W

now let A, B ∈ W

A = -A^T       B = -B^T

(A+B)^T = A^T + B^T

= -A - B

- ( A + B )

⇒ A + B = -( A + B)^T

∴ A + B ∈ W.

∝ ∈ | R

(∝.A)^T = ∝A^T

= ∝( -A)

= -( ∝A)

(∝A) = -( ∝A)^T

∴ ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

A ∈ W

A = -AT

A = \left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]

= a\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] +b\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] +c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]

therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

8 0
3 years ago
-5 can be thought of as "the opposite of 5". TRUE or FALSE
kap26 [50]

Answer:

True

Step-by-step explanation:

8 0
3 years ago
The three sides of a triangle are n, 3n + 5, and 4n − 9. If the perimeter of the triangle is 68 feet, what is the length of each
MissTica
4n - 9 + 3n + 5 + n = 68

combine like terms

8n - 4 = 68

addition property of equations

8n = 72

division property of equality

n = 9

SIDES:

n = 9

3n + 5 = 32

[ 3(9) + 5 = 32 ]

4n - 9 = 27

[ 4(9) - 9 = 27 ]
5 0
4 years ago
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