The given data is Magnification, M = 15
Length of the tube , L = 16 cm
The focal length of the lens can be calculated by:
M = L/F
Substituting the value, we get:
15 = 16/f
f = 16/15
f = 1.067 cm
Using the equation of magnification we get,
M = v/u
Substituting the values we get:
15 = v/u
v = 15 u
With the help of lens formula, calculate the object distance:
1/f = 1/v + 1/u
Substituting the value we get,
1/1.067 = 1/15u + 1/u
0.937 = 1.067/u
u = 1.13 cm or 1.1 cm.
Hence, the object distance is 1.1 cm.
The enzyme glucose oxidase isolated<span> from the </span>mold penicillium notatum catalyzes<span> the</span>oxidation<span> of </span>β-d-glucose<span> to </span>d-glucono-δ-lactone<span>. this </span>enzyme<span> is highly - 6641578. ... </span>enzyme<span> is </span>hihly specific<span> for the </span>β anomer<span> of </span>glucose<span> and </span>does not affect<span> the </span>α anomer<span>. in </span>spite<span> of this </span>specificity, the<span>reaction catalyzed</span>
Answer:
Box 1: AA
Box 2: Aa
Box 3: AA
Explanation:
In order to figure out the pedigree, you first have to do a punnet square- kind of like cross-multiplying. EX: For the first box: Aa x AA
For box one, we know that it is Aa, and not AA, because box 2 has to be AA.
We know that because Aa X Aa would give us some "aa" offspring which we do not see in the last generation (see 2nd pic). The only way to get no "aa" offspring is to have an AA X Aa cross.
