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AlekseyPX
3 years ago
10

Data are collected about the amount of time, in minutes, each member of the lacrosse team spends practicing. How does a single o

utlier change the mean of the collected data
Mathematics
1 answer:
Serjik [45]3 years ago
8 0

it can change the average

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0.75y-1.5y+0.5=5 I need answers to this asap
Mnenie [13.5K]

Answer:

y = -6

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

0.75y−1.5y+0.5=5

0.75y+−1.5y+0.5=5

(0.75y+−1.5y)+(0.5)=5(Combine Like Terms)

−0.75y+0.5=5

−0.75y+0.5=5

Step 2: Subtract 0.5 from both sides.

−0.75y+0.5−0.5=5−0.5

−0.75y=4.5

Step 3: Divide both sides by -0.75.

Hope this helps!

:)

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-Josh

6 0
2 years ago
A solid cylinder has a radius of 4 cm and a length of 8 cm is melted down and recast in a solid cube find the dimension of the c
zhannawk [14.2K]

Answer:

7.37108cmx7.37108cmx7.37108cm

Step-by-step explanation:

Find the volume of the cylinder then take the cube route of that. You should end up with ~7.38108cm which is the length, width, and height of your cube. The volume is 402.12386cm cubed.

5 0
3 years ago
Read 2 more answers
The ratio of the sales tax to the amount of a purchase is a fixed number in Town Q. The table shows the sales tax for a purchase
Volgvan
I think number #29 is A but may be B and number #30 is C
8 0
3 years ago
Please help with this question
stiks02 [169]

Answer:

I don't know

Step-by-step explanation:

7 0
2 years ago
WILL MARK AS BRAINLIEST!!! 5. A 2011 study by The National Safety Council estimated that there are nearly 5.7 million traffic ac
Artyom0805 [142]

Answer:

Step-by-step explanation:

Hello!

Regarding the reasons that traffic accidents occur:

28% are caused by distracted drivers using cell phones or texting

11% of the drivers' user their phones at any time

The probability of a driver having an accident is 5.26%

a)

DC = event that a randomly selected driver is using a cell phone.

P(DC)= 0.11

b)

TA = event that a randomly selected driver has a traffic accident.

P(TA)= 0.0526

c) and f)

If both events are related, i.e. dependent, then you would expect that the occurrence of one of these events will affect the probability of the other one. If they are not related, i.e. independent events, then their probabilities will not be affected by the occurrence of one or another:

If both events are independent P(TA|DC)= P(TA)

If they are dependent, then:

P(TA|DC)≠ P(TA)

P(TA|DC)= 0.28

P(TA)= 0.0526

As you can see the probability of the driver having an accident given that he was using the cell phone is different from the probability of the driver having an accident. This means that both events are related.

d) and e)

You have to calculate the probability that "the driver was distracted with the phone given that he had an accident", symbolically P(DC|TA)

P(DC|TA) = \frac{P(DCnTA)}{P(TA)}

P(TA|DC)= \frac{P(TAnDC}{P(DC)} ⇒ P(DC∩TA)= P(TA|DC)*P(DC)= 0.28 *  0.11= 0.0308

P(DC|TA) = \frac{0.0308}{0.0526}= 0.585= 0.59

I hope this helps!

3 0
3 years ago
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