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3 years ago

Which is equivalent to 3sqrt8^1/4x

Mathematics

1 answer:

fiasKO [112]3 years ago

3 0

Answer:

12 √8 ×

Step-by-step explanation:

There is two many variables in that I believe you meant. What is equivalent to 3 square root 8^1/4x? =12 √8 × . Hopefully this helped you .

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Can anyone help me with this problem???

jasenka [17]

Note that x is the hypotenuse of a right triangle. Applying the Pyth. Thm.,

x^2 = 2^2 + 6^2, or x^2 = 4 + 36 = 40.

Thus, the hypotenuse is +sqrt(40), or 2sqrt(10).

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3 years ago

Write number to make each line have the sum 7

DochEvi [55]

Write each line to make the sum 7 it say I can't tell y'all the answer dang alot of people need help I got 18 seconds to tell yall

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4 years ago

Please answer the following:

konstantin123 [22]

Answer:

26 1/2

Step-by-step explanation:

convert 4 5/12 into 53/12

multiply 53/12 by 6 to get 53/2

turn 53/2 into a mixed number = 26 1/2

3 0

3 years ago

Read 2 more answers

7. In A.ABC. JB and KA are medians, JK = 10x - 12, AB = 9x + 18, JM = 21, KM = 23. AJ = 60. and

Juliette [100K]

Answer:

A) JK and AB =

$[tex] \boxed{( \theta) = \f{12}{( \theta)} }$ So, =》 $\dfrac{10}{5} = \dfrac{1}{ \( \theta) }$ =》 $\( \theta) = \dfrac{5}{2}$ [/tex]

B) AABC

$[tex] \boxed{( \theta) = {1}{( \theta)} }$ So, $23}{-18=\\Ans } \boxed$

C) AABM:

$[tex] e \fbox{: }$ The value of k for which $\sin(jm) = \cos(x)$ is $\dfrac{\p}{2}$ ans[/tex]

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3 0

3 years ago

Algebra 1 question 4.

Brrunno [24]

Greetings!

To start this problem, let's first assign a variable for the missing, consecutive odd numbers. Since they are consecutive and odd, we add two.

<u>Proof:</u> <em>3-1=2, 5-3=2</em>

The first, consecutive, odd number: $x$

The second, consecutive, odd number: $x+2$

The third, consecutive, odd number: $x+4$

The fourth, consecutive, odd number: $x+6$

The sum of the values are equal to 3 times the sum of the first two numbers, of which this is equal to 35 less than the fourth number. Let's create an equation to simplify this:

$3((x)+(x+2))=(x+6)-35$

Complete the operations inside the parenthesis:

$3(2x+2)=(x+6)-35$

Distribute the parenthesis (utilizing the distributive property)

$(((2x)(3))+((2)(3)))=(x+6)-35$

$(6x+6)=(x+6)-35$

Simplify both sides:

$6x+6=x-29$

Add -6 and -x to both sides of the equation:

$(6x+6)+(-6)+(-x)=(x-29)+(-6)+(-x)$

$5x=-35$

Divide both sides of the equation by 5:

$\frac{5x}{5}=\frac{-35}{5}$

$x=-7$

If $x$ is equal to -7:

$x+2=-5$

$x+4=-3$

$x+6=-1$

The four numbers are:

$\boxed{-7,-5,-3,-1}$

I hope this helps!

-Benjamin

4 0

3 years ago

Read 2 more answers