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2 years ago

5

Winston bought an encyclopedia priced at $42. Shipping and handling cost anadditional 30% of the price. What was the total cost

of the encyclopedia, in cluding shipping and handling?

1 answer:

Sergio039 [100]2 years ago

3 0

Answer:

42.3

Sorry I haven't been answering your questions I'm just behind on homework.

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Sales of 10000 increased by 65% each year write a function that represents the situation

erastovalidia [21]

Answer: $y=10000(1.65)^x$

Step-by-step explanation:

Given: The sales of 10000 increased by 65% each year .

Let x be the number of years.

The rate of growth=65%= 0.65

The exponential growth function is given by

$y=A(1+r)^x$

, where A is initial amount and r is the rate of growth in decimal.

Then the increase in the sales id given by :-

$y=10000(1+0.65)^x\\\Rightarrow\ y=10000(1.65)^x$

6 0

2 years ago

The function in Exercise represents the rate of flow of money in dollars per year. Assume a 10-year period at 8% compounded cont

anzhelika [568]

Answer:

a) The present value is 688.64 $

b) The accumulated amount is 1532.60 $

Step-by-step explanation:

<u>a)</u><u> The preset value equation is given by this formula:</u>

$P=\int^{T}_{0}f(t)e^{-rt}dt$

where:

T is the period in years (T = 10 years)
r is the annual interest rate (r=0.08)

So we have:

$P=\int^{T}_{0}(0.01t+100)e^{-rt}dt$

Now we just need to solve this integral.

$P=\int^{T}_{0}0.01te^{-rt}dt+\int^{T}_{0}100e^{-rt}dt$

$P=e^{-0.08t}(-1.56-0.13t)|^{10}_{0}+1250e^{-0.08t}|^{10}_{0}$

$P=0.30+688.34=688.64 $$

The present value is 688.64 $

<u>b)</u><u> The accumulated amount of money flow formula is:</u>

$A=e^{r\tau}\int^{T}_{0}f(t)e^{-rt}dt$

We have the same equation but whit a term that depends of τ, in our case it is 10.

So we have:

$A=e^{r\tau}\int^{T}_{0}(0.01t+100)e^{-rt}dt=e^{0.08\cdot 10}P$

$A=e^{0.08\cdot 10}688.64=1532.60 $$

The accumulated amount is 1532.60 $

Have a nice day!

6 0

2 years ago

SOMEONE PLEASE HELP<br> find the greatest common factor <br> 14g5h2, 56g3h4, 77g3h2

andrezito [222]

Answer:

$\large\boxed{GCF(14g^5h^2,\ 56g^3h^4,\ 77g^3h^2)=g^3h^2}$

Step-by-step explanation:

$14g^5h^2=2\cdot7\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot g\cdot g\cdot \boxed{h}\cdot \boxed{h}\\\\56g^3h^4=2\cdot2\cdot2\cdot7\cdot\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}\cdot h\cdot h\\\\77g^3h^2=7\cdot11\cdot\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}\\\\GCF(14g^5h^2,\ 56g^3h^4,\ 77g^3h^2)=\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}=g^3h^2$

8 0

2 years ago

Please answer this correctly

Alenkasestr [34]

Answer:

5/12

Step-by-step explanation:

The probability of rolling a number greater than 1 is 5/6, because 5 numbers on a 6-sided dice are greater than 1.

The probability of rolling an even number is 3/6, because 3 numbers on a 6-sided dice are even numbers.

$5/6 \times 3/6$

$=15/36$

$=5/12$

7 0

3 years ago

10 points! + Brainly

Cerrena [4.2K]

Answer:

3n² + 4n - n

3 x 7² + 4 x 7 - 7

first do the exponent because there is no parentheses

3 x 49 + 4 x 7 - 7

second do either multiplication or division with ever is closes to the left

147 + 4 x 7 - 7

147 + 28 - 7

third do either addition or subtraction which ever is closes to the left

175 -7

168

finally the answer is 168

5 0

2 years ago