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3 years ago

(05.08A)Two similar triangles are shown on the following coordinate grid:

Mathematics

2 answers:

ziro4ka [17]3 years ago

6 0

So the answer is Dilation by scale factor of 2 followed by reflection over the y-axis

e-lub [12.9K]3 years ago

5 0

Dilation by a scale factor of 2 followed by reflection over y-axis

hope this helps

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A 52 foot ladder is set against the side of the house so that it reaches up 48 feet .if jevonte grabs the ladder at its base and

Vesnalui [34]

Answer:

Step-by-step explanation:

The way to approach this that makes the most sense to a student would be to find out how far from the house the ladder currently is, then add 3 feet to that and do the problem all over again. This is right triangle stuff...Pythagorean's Theorem in particular. The ladder is the hypotenuse, 52 feet long. The height of the rectangle is the distance the ladder is up the side o the house, 48 feet. We plug those into Pythagorean's Theorem and solve for the distance the ladder is from the house:

$52^2=48^2+x^2$ and

$2704=2304+x^2$ and

$x^2=400$ so

x = 20. Now if we add the 3 feet that the ladder was pulled away from house, the distance from the base of the ladder to the house is 23 feet, the ladder is still 52 feet long, but what's different is the height of the ladder up the side of the house, our new x:

$52^2=23^2+x^2$ and

$2704=529+x^2$ and

$2175=x^2$ so

x = 46.6 feet

6 0

3 years ago

Solve |2x - 5| = 4. {x | x = -4.5 or x = 4.5} {x | x = 0.5 or x = 4.5} {x | 0.5 < x < 4.5}

kotykmax [81]

Answer:

{x | x = 0.5 or x = 4.5}

Explanation:

Before we begin, remember that:

The modulus gives the positive value of what's inside it.

This means that:

|a| = |-a| = a

Now, for the given, we have:

|2x-5| = 4

From the above rule, we can deduce that:

either:

2x - 5 = 4

2x = 4 + 5 = 9

x = 4.5 ............> first solution

Or:

2x - 5 = -4

2x = 5-4 = 1

x = 0.5 ..........> second solution

Now, we check:

at x = 4.5: |2(4.5)-5| = |9-5| = |4| = 4 ..........> first solution verified

at x = 0.5: |2(0.5)-5| = |1-5| = |-4| = 4 .........> second solution verified

Hope this helps :)

6 0

3 years ago

QUESTION 11

notsponge [240]

Answer:

Step-by-step explanation:

3( 2 + 2 ) - 4

3( 4 ) - 4

12-4

3 0

3 years ago

I need help! I'm *so* confused! I will mark Brainliest

Naddik [55]

Answer:

(-2,21)

Step-by-step explanation:

2 days ago, Paulo's commute time was halfway between his commute times 8 and 9 days ago.

8 days ago means that x-coordinate -8 represents this day. Count 8 units to the left and find that when x = -8, y = 24 minutes.

9 days ago means that x-coordinate -9 represents this day. Count 9 units to the left and find that when x = -9, y = 18 minutes.

Find halfway commute time between points (-8,24) and (-9,18):

$y=\dfrac{24+18}{2}=\dfrac{42}{2}=21,$

then coordinates that Paulo should graph are

(-2, 21)

(-2 means 2 days ago, 21 is the halfway)

5 0

3 years ago

You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confide

FrozenT [24]

Question:

You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of $114.00. Assume the population standard deviation is $15.30. Construct a 90% confidence interval for the population mean.

Answer:

At the 90% confidence level, confidence interval = 110.2484 < μ < 117.7516

At the 95% confidence level, confidence interval = 109.53 < μ < 118.48

The 95% confidence interval is wider

Step-by-step explanation:

Here, we have

Sample size, n = 45

Sample mean, $\bar x$ = $114.00

Population standard deviation, σ = $15.30

The formula for Confidence Interval, CI is given by the following relation;

$CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}$

Where, z is found for the 90% confidence level as ±1.645

Plugging in the values, we have;

$CI=114\pm 1.645 \times \frac{15.3}{\sqrt{45}}$

or CI: 110.2484 < μ < 117.7516

At 95% confidence level, we have our z value given as z = ±1.96

From which we have $CI=114\pm 1.96 \times \frac{15.3}{\sqrt{45}}$

Hence CI: 109.53 < μ < 118.48

To find the wider interval, we subtract their minimum from the maximum as follows;

90% Confidence level: 117.7516 - 110.2484 = 7.5

95% Confidence level: 118.47503 - 109.5297 = 8.94

Therefore, the 95% confidence interval is wider.

8 0

3 years ago

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