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3 years ago

(05.08A)Two similar triangles are shown on the following coordinate grid:

Mathematics

2 answers:

ziro4ka [17]3 years ago

6 0

So the answer is Dilation by scale factor of 2 followed by reflection over the y-axis

e-lub [12.9K]3 years ago

5 0

Dilation by a scale factor of 2 followed by reflection over y-axis

hope this helps

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WILL GIVE BRAINLIEST TO BEST ANSWER- DUE TODAY

solong [7]

Quadratic Formula: $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , with a = x^2 coefficient, b = x coefficient, and c = constant.

Firstly, using our equation plug in the values into our equation (a = 1, b = -4, and c = 3):

$x=\frac{4\pm \sqrt{(-4)^2-4*1*3}}{2*1}$

Next, solve the exponent and multiplications:

$x=\frac{4\pm \sqrt{16-12}}{2}$

Next, solve the subtraction:

$x=\frac{4\pm \sqrt{4}}{2}$

Next, solve the square root:

$x=\frac{4\pm 2}{2}$

Next, you are going to solve this equation twice - once with the + symbol, once with the - symbol as such:

$x=\frac{4+2}{2}\\\\x=\frac{6}{2}\\\\x=3\\\\\\x=\frac{4-2}{2}\\\\x=\frac{2}{2}\\\\x=1$

<u>Your zeros (x-intercepts) are 3 and 1. These solutions are real and rational.</u>

4 0

4 years ago

10TH GRADE GEOMETRY PLEASE HELP ME!

fredd [130]

The Figures that are shown in the diagram are
Ray CD
and
Segment CD

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B5.29%7D%20%20%20%3D%20" id="TexFormula1" title=" \sqrt{5.29} = " alt=" \sqrt{5.

Alla [95]

Answer:

2.3

Step-by-step explanation:

In this case we are going to use the 'Babylonian Method' to get the square root of any positive number.

We must set an error for the final result. Say, smaller than 0.01. In other words we will try to find the square root value with at least 1 correct decimal places.

Step 1:

Divide the number (5.29) by 2 to get the first guess for the square root .

First guess = 5.29/2 = 2.645.

Step 2:

Divide 5.29 by the previous result. d = 5.29/2.645 = 2.

Average this value (d) with that of step 1: (2 + 2.645)/2 = 2.3225 (new guess).

Error = new guess - previous value = 2.645 - 2.3225 = 0.3225.

0.3225 > 0.01. As error > accuracy, we repeat this step again.

Step 3:

Divide 5.29 by the previous result. d = 5.29/2.3225 = 2.2777179763.

Average this value (d) with that of step 2: (2.2777179763 + 2.3225)/2 = 2.3001089882 (new guess).

Error = new guess - previous value = 2.3225 - 2.3001089882 = 0.0223910118.

0.0223910118 > 0.01. As error > accuracy, we repeat this step again.

Step 4:

Divide 5.29 by the previous result. d = 5.29/2.3001089882 = 2.299891017.

Average this value (d) with that of step 3: (2.299891017 + 2.3001089882)/2 = 2.3000000026 (new guess).

Error = new guess - previous value = 2.3001089882 - 2.3000000026 = 0.0001089856.

0.0001089856 <= 0.01. As error <= accuracy, we stop the iterations and use 2.3000000026 as the square root.

So, we can say that the square root of 5.29 is 2.3 with an error smaller than 0.01 (in fact the error is 0.0001089856). this means that the first 3 decimal places are correct. Just to compare, the returned value by using the javascript function 'Math.sqrt(5.29)' is 2.3.

Note: There are other ways to calculate square roots. This is only one of them.

Normal:

The square root of 5.29 is defined as the only positive real number such that, multiplied by itself, it is equal to 2.3.

The square root of 5.29 can be written as (5.29)1/2. So,

(5.29)1/2 = (2.3 × 2.3)1/2

(5.29)1/2 = [(2.3)2]1/2

(5.29)1/2 = (2.3)2/2

(5.29)1/2 = (2.3)1

Thus,

√5.29 = 2.3

3 0

3 years ago

A driver travels for four days and covers 900 km in total. he covers 223 km, 188 km and 309 km on the first three days. how far

liraira [26]

Answer:

i guess for this it would go like:-

total distance covered by the driver in four days(d)= 900km

distance covered by him in first day(d1) = 223 km

distance covered by him on second day(d2) =188km

distance covered by him on third day(d3)= 309 km

now,

distance covered on fourth day (d4)= 900-223-188-309

= 180 km

Step-by-step explanation:

here, the total distance is given i.e 900 km. similarly the distance covered by the driver on the consecutive days are also giver. so here we subract the distance covered by the driver in all the three days from the total distance it covers. it would gibe us the distance covered by him on the fourth day. since, it is the the left out distance that the driver has to cover.

hope it helps..

6 0

3 years ago

What are the solutions to |5x+2|=8

netineya [11]

Decimal Form:

x=2,−1.2

8 0

4 years ago