Answer:
As the calculated F lies in the acceptance region therefore we conclude that there is not sufficient evidence to support the claim that the variability in concentration may differ for the two companies. Hence Ha is rejected and H0 is accepted.
Step-by-step explanation:
As we suspect the variability of concentration F - test is applied.
n1=10 s1=4.7
n2=16 s2=5.8
And α = 0.05.
The null and alternate hypothesis are
H0: σ₁²=σ₂² Ha: σ₁²≠σ₂²
The null hypothesis is the variability in concentration does not differ for the two companies.
against the claim
the variability in concentration may differ for the two companies
The critical region F∝(υ1,υ2) = F(0.025)9,15= 3.12
and 1/F∝(υ1,υ2) = 1/3.77= 0.26533
where υ1= n1-1= 10-1= 9 and υ2= n2-1= 16-1= 15
Test Statistic
F = s₁²/s₂²
F= 4.7²/5.8²=0.6566
Conclusion :
As the calculated F lies in the acceptance region therefore we conclude that there is not sufficient evidence to support the claim that the variability in concentration may differ for the two companies. Hence Ha is rejected and H0 is accepted.
C because there both equal. its just that the other one doesn't have a 0 on the end but there equal.
Answer:
-1.375< -1
Step-by-step explanation:
Answer:
Step-by-step explanation:
Sum of exterior angles of regular polygons is 360°.
If each angle measures 15°, then the number of sides:
- 15n = 360
- n = 360/15
- n = 24
Answer:
20,000 particles
Step-by-step explanation:
Here we are given that the amount if radioactive particles has come down to 40,000 from 80,000 in 80 years . Hence by the definition of Half Life,the half life of the item is 80 years.
Now we are asked to guess the number of radioactive particles after 80 years. As we already know that , the half life of material is 80 years , the number of radioactive particles will be reduced to its half in 80 years. Hence the number of radioactive particles after 80 years is 20,000
