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3 years ago

must a function that is decreasing over a given interval always be negative over that same interval explain

Mathematics

2 answers:

kolbaska11 [484]3 years ago

8 0

check the picture below.

notice, a function that is decreasing, namely have a negative slope, doesn't have to be negative.

Dimas [21]3 years ago

7 0

Answer:

Step-by-step explanation:

For a function to be decreasing over an interval, the outputs on the function are getting smaller as the inputs of the function are getting larger, but the outputs could be positive or negative. For a function to be negative over an interval, the outputs must be negative, while the inputs could be positive or negative.

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PLEASE HELP A store is having a sale on chocolate chips and walnuts. For 5 pounds of chocolate chips and 3 pounds of walnuts, th

Stells [14]

Answer:

Chocolate Chips cost $2.25 and Walnuts cost $3.25 per pound each

Step-by-step explanatChocion:

Let x = cost of pounds of chocolate chip cookies and y = cost of pounds of walnuts.

From the question, we get 5x+3y = 21 and 2x+6y = 24. To solve the equation, we use substitution. From the first equation, we get y = (21-5x)/3. We substitute the y into the second equation to get 2x + 6(21-5x)/3 = 24. This turns out to be 2x+(42-10x) = 24. Adding like terms you should get 42-8x = 24. Solving for x, x = $2.25 per pound. Plugging this into the first equation, we get 5(2.25)+3y = 21. Solving for y, we get $3.25 per pound of walnuts. If we plug in the numbers into the 2 equations, we will get the right total.

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3 years ago

Kenny is packing cans into bags at the food bank he cn pack 8 cans into each bag how many bags how many bags will kenny need for

Sholpan [36]

1056cans/ 8 cans=132 bags

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3 years ago

Element X decays radioactively with a half life of 12 minutes. If there are 690 grams of Element X, how long, to the nearest ten

Alexeev081 [22]

Answer:

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Step-by-step explanation:

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3 years ago

Write the expression for the Area of the polygon BORT MO 6 A= O A = 6m + mp O A = mp + 1/2(6m) O A = mp + 6p

anyanavicka [17]

We are asked to determine the area of the given figure. To do that we will divide the figure into a square and a triangle. The area of the square is the product of its dimension, therefore, the area is:

$A_{sq}=mp$

The area of the triangle is given by the following formula:

$A_t=\frac{bh}{2}$

Where "b" is the base and "h" is its height. Replacing the values:

$A_t=\frac{(6)(m)}{2}=\frac{1}{2}6m$

The total area is the sum of both areas:

$A=A_{sq}+A_t$

replacing the areas:

$A=mp+\frac{1}{2}6m$

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1 year ago

Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5

lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer: v = 5v + 4u + 1.5sin(3t),

1.5sin(3t)

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t) where u'(1) = 2.5 u(1) = 1

v represents the "velocity function" i.e v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v' = 5u' + 4u + 1.5sin(3t) ( given that u" - 5u' - 4u = 1.5sin(3t) )

= 5v + 4u + 1.5sin(3t) ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt $\left[\begin{array}{ccc}u&\\v&\\\end{array}\right]$ = $\left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]$ $\left[\begin{array}{ccc}u&\\v&\\\end{array}\right]$ + $\left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]$

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

$\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]$ = $\left[\begin{array}{ccc}1\\2.5\\\end{array}\right]$

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3 years ago