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dusya [7]
3 years ago
10

CAN SOMEONE PLEASE HELP WILL MARK BRAINLIEST I JUST NEED HELP WITH THE LAST ONE THE GREEN SECTION

Mathematics
1 answer:
Molodets [167]3 years ago
5 0
There isn’t any pictures....
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PLS help ill give 50 points to the person who answers correctly The instructions of an art project tell students to cut a piece
MrMuchimi

Answer:

no guaranteed classification

Step-by-step explanation:

We know that the quadrilateral has two pairs of congruent sides. Both a rectangle and a parallelogram have two pairs of congruent sides. The difference between them is their angles. But we don't know anything about the angles in the figure, so we cannot know which kind it is.

4 0
3 years ago
Selena earned $200 last month babysitting. She used 25 of her earnings to buy a video game. How much did she spend on the video
babymother [125]

Answer:

See below

Step-by-step explanation:

<u>Is that $25 or 35%?</u>

If $25, she spent $25.

If 25%, she spent (0.25)*(200) = $50.

3 0
2 years ago
3 less than the quotient of 20 and x
UkoKoshka [18]
It would be (20/x) -3
3 0
3 years ago
Perform the indicated operation. 6 - 2i/5 + 3i =
fgiga [73]
I am gonna assume it is C)9/4 - 1/2i
5 0
3 years ago
Read 2 more answers
A dog breeder would like to know how many Dalmatian puppies are typically born in a litter. He conducts some research and select
podryga [215]

Answer:

c. 6.2 ± 2.626(0.21)

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 101 - 1 = 100

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.626

The confidence interval is:

\overline{x} \pm M

In which \overline{x} is the sample mean while M is the margin of error.

The distribution of the number of puppies born per litter was skewed left with a mean of 6.2 puppies born per litter.

This means that \overline{x} = 6.2

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.626\frac{2.1}{\sqrt{101}} = 2.626(0.21)

In which s is the standard deviation of the sample and n is the size of the sample.

Thus, the confidence interval is:

\overline{x} \pm M = 6.2 \pm 2.626(0.21)

And the correct answer is given by option c.

5 0
3 years ago
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