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2 years ago

CAN SOMEONE PLEASE HELP WILL MARK BRAINLIEST I JUST NEED HELP WITH THE LAST ONE THE GREEN SECTION

Mathematics

1 answer:

Molodets [167]2 years ago

5 0

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Whats the equation of the circle whose center and radius are given.

mote1985 [20]

(x+2)^2+(y+5)^2=1
...........

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2 years ago

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EASY 6TH GRADER MATH

Rudik [331]

Answer:

Step-by-step explanation:

She is wrong the answer is 27, all you have to do is multiply the number by the percentage as a decimal (.45)

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2 years ago

Mr. Garcia has 3/4 yard of ribbon to make badges for winners at a side spray uses 1/8 yard of ribbon for each badge how many bad

Anton [14]

Answer:

The total number of badges miss Garcia can make=6

Step-by-step explanation:

Step 1: Express the total length of ribbon

Use the expression below;

R=B×N

where;

R=total length of ribbon Garcia has

B=length per badge

N=number of badges made

In our case;

R=3/4 yard

B=1/8 yard

N=n

replacing;

(3/4)=(1/8)×n

n=(3/4)×8

n=6

The total number of badges miss Garcia can make=6

8 0

3 years ago

Add & give answer in lowest (reduced) form:<br> 1/6 + 3/8

ANEK [815]

1/6 + 3/8= 4/24 + 9/24= 13/24

4 0

3 years ago

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. Calculate the missing terms of the geometric sequence. 3072,?,?,?,12,.... Select all that apply.

Troyanec [42]

Answer:

The missing terms of the geometric series are

A. $-768,192,-48$

and

B. $768,192,48$

Step-by-step explanation:

The given geometric sequence is $...,3072,?,?,12,...$ .

The second and sixth term of the geometric sequence are $3072$ and $12$ respectively.

Recall that the nth term of a geometric sequence is given by,

$t_n=ar^{n-1}$ .

This implies that the second term will be,

$3072=ar^{2-1}$ .

$\Rightarrow 3072=ar---(1)$ .

Also the 6th term is

$12=ar^{6-1}$ .

$12=ar^{5}---(2)$ .

We divide equation (2) by (1) to get,

$\frac{ar^5}{ar}=\frac{12}{3072}$

$\Rightarrow r^4=\frac{1}{256}$

$\Rightarrow r=\pm \sqrt[4]{\frac{1}{256} }$

$r=\pm \frac{1}{4}$

$r=\frac{1}{4}$

We get,

$t_3=3072\times\frac{1}{4} =768$

$t_4=768\times\frac{1}{4} =192$

$t_5=192\times\frac{1}{4} =48$

But If

$r=-\frac{1}{4}$

We get,

$t_3=3072\times\frac{-1}{4} =-768$

$t_4=-768\times\frac{-1}{4} =192$

$t_5=192\times\frac{-1}{4} =-48$

Therefore the correct answer is A and B.

6 0

2 years ago

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