Question

What is 8x squared = 56 rounded to the nearest tenth equal?

Answer 1

$8x^2=56\ /:8\\x^2=7\\x^2-7=0\\(x- \sqrt{7} )(x+ \sqrt{7} )=0\\x-\sqrt{7}=0\ \ \ \ \ or\ \ \ \ \ x+\sqrt{7}=0\\x=\sqrt{7}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-\sqrt{7}\\ \\ x\approx2.65\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x-\approx2.65$

Answer 2

8x^2=56
divide noth sides by 8
x^2=7
square root both sides
x=2.65 or -2.65