Minimum value is equal to x=8, y=-4
First find the derivative of the original equation which equals= d/dx(x^2-16x+60) = 2x - 16
at x=8, f'(x), the derivative of x equals zero, so therefore, at point x = 8, we have a minimum value.
Just plug in 8 to the original equation to find the answer for the minimum value.
Answer:
Two shapes are similar when they have the same shape while their sizes may be the same or different
Therefore, two similar shapes are shapes that have a relationship such that the dimensions of one of the shapes can be obtained from the dimensions of the other shape by multiplying by a scale factor
All circles have the same shape and are defined by their center and radius
Given circle with center at 'x' and radius 'r' and circle with center 'y' and radius 's', then there exist a scale factor a = s/r such that we have;
r × a = s
Where a = s/r, we get;
r × s/r = s
We can therefore, obtain a circle with with the same size as the circle with center 'y' and radius 's' by multiplying the radius of the circle with center at 'x' and radius 'r' by a
Therefore the circle with center at 'x' and radius 'r' is similar to the circle with center 'y' and radius 's'
Step-by-step explanation:
Answer:
x2-4
Step-by-step explanation:
Answer:
add all of these mesurements together 2.3 + 0.8 + 1.9 then do it times 2
the awnser is 10
Step-by-step explanation:
The first one is incorrect. i’d pick that one.
