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NISA [10]
3 years ago
14

PLEASE HELP WILL GIVE BRAINLIEST

Mathematics
1 answer:
dolphi86 [110]3 years ago
7 0

?????????????????????????m

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Find the value of X. What is x and how do you solve for y first.
11111nata11111 [884]

Answer:

id.k but i hope this wuote helps u have a great day :) :)

Step-by-step explanation:

Everything will be okay in the end. If it’s not okay, it’s not the end

Have a nice day :) :) :)

5 0
2 years ago
How do You supposed to do this i need many method to do it.
defon
I like the substitution method. Which is when you make one equation equal only x or y and plug it into the other equation)

There is also the graphing method. If you graphed it, it might not be quite as accurate (at least on hand, on computer you would be pretty exact)

Then there is the elimination method. You multiply one of the equations by a coefficient so that you can eliminate x or y from the equation. 
4 0
3 years ago
Sam has a budget of $24 to buy ham and cheese to make sandwiches. If he bought only ham, he could buy 8 lb. If he bought only ch
fomenos

Answer:

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th
olya-2409 [2.1K]

Answer:

\frac{BE}{EC} =\frac{1}{3}

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

\frac{BK}{CK} =\frac{1}{4}

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE                ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE     ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK  and Δ EBK are similar

so we have

\frac{AD}{BE} =\frac{DK}{BK}

\frac{AD}{BE} =\frac{4}{1}

\frac{BC}{BE}=\frac{4}{1}     ( ABCD is parallelogram so AD=BC)

\frac{BE+EC}{BE}=\frac{4}{1}         ( BC= BE+EC)

\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}

1+\frac{EC}{BE}=4

\frac{EC}{BE}=3  ( subtracting 1 from both side )

\frac{EC}{BE}=\frac{3}{1}

taking reciprocal both side

\frac{BE}{EC} =\frac{1}{3}


8 0
3 years ago
Find the standard form of the equation of the parabola with the given characteristics
lord [1]

Answer:

Step-by-step explanation:

The standard equation of a parabola is

y² = 4ax

where, a is the focus,

The coordinates of the centre of parabola is (0,0)

coordinates of focus is (a, 0)

It is symmteric about the x axis

the equation of directrix is x = -a.

5 0
3 years ago
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