Find the cost in dollars of the operating a 60-W lamp continuously for 1 week when the power utility rate is 18 cents/kWh .
1 answer:
<h2>
Answer:</h2>
The cost in dollars is:
$ 1.8144
<h2>
Step-by-step explanation:</h2>
It is given that:
The 60-W lamp is operated continuously for 1 week.
We know that:
1 week=7 days
and 1 day=24 hours
This means that:
1 week=24×7
i.e. 1 week= 168 hours
Also, 1 kW=1000 W
This means that:
1 W=0.001 kW
Hence,
60-W=0. 060 KW
i.e. Power= 0.60 KW
Hence, the energy consumed is:
Energy=Power×Time
i.e.
Energy=0.060×168
i.e.
Energy=10.08 KWh
Also, cost of 1 KWh=18 cents
We know that:
1 cent=0.01 dollar
This means that:
18 cents=0.18 dollar
i.e.
Cost of 1 KWh=$ 0.18
Hence, cost of 10.08 KWh is: $ (0.18×10.08)
i.e.
Cost of 10.08 KWh is: $ 1.8144
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