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zhannawk [14.2K]
3 years ago
7

What is the difference for -22 - (-26)​

Mathematics
1 answer:
Alenkasestr [34]3 years ago
8 0

Answer:

4

Step-by-step explanation:

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Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values
Vesnalui [34]

The Lagrangian is

L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)

with critical points where the partial derivatives vanish.

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}

L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda

L_\lambda=x^2+y^2-9=0

Substitute x,y into the last equation and solve for \lambda:

\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6

Then we get two critical points,

(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)

We get an absolute maximum of 3\sqrt{17}\approx12.369 at the second point, and an absolute minimum of -3\sqrt{17}\approx-12.369 at the first point.

4 0
3 years ago
Find the slope of the equation
andreyandreev [35.5K]

Answer:

In my guess I'll go for Slope = -\frac{4}{5}  y-intercept = 10

7 0
3 years ago
Parallel lines r and s are cut by two transversals, parallel lines t and u.
romanna [79]

Answer:

the answer is <u><em>2</em></u> on edge

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
You are looking at a convention bid that requires 100,000 square feet of meeting space. You have one room at 200 ft x 200 ft, an
Alla [95]
The 2 rooms only add up to 45,000 square feet (150 x 150 x 2) and the larger room is only 40,000 square feet (200 x 200) so this only gives you 85,000 square feet (40,000 + 45,000) which is not enough for the 100,000.
7 0
3 years ago
Select two choices that are true about the function f(x)=23x+14/x
WINSTONCH [101]

Answer:

There is an asymptote at x = 0

There is an asymptote at y = 23

Step-by-step explanation:

Given the function:

(23x+14)/x

Vertical asymptote is gotten by equating the denominator to zero

Since the denominator is x, hence the vertical asymptote is at x = 0. This shows that there is an asymptote at x = 0

Also for the horizontal asymptote, we will take the ratio of the coefficient of the variables in the numerator and denominator

Coefficient of  x at the numerator = 23

Coefficient of x at the denominator = 1

Ratio = 23/1 = 23

This means that there is an asymptote at y = 23

8 0
3 years ago
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