1 Simplify n+5+-m-3n+8n+5+−m−3n+8 to n+5-m-3n+8n+5−m−3n+8.
11-2m-(n+5-m-3n+8)11−2m−(n+5−m−3n+8)
2 Collect like terms.
11-2m-((n-3n)+(5+8)-m)11−2m−((n−3n)+(5+8)−m)
3 Simplify (n-3n)+(5+8)-m(n−3n)+(5+8)−m to -2n+13-m−2n+13−m.
11-2m-(-2n+13-m)11−2m−(−2n+13−m)
4 Remove parentheses.
11-2m+2n-13+m11−2m+2n−13+m
5 Collect like terms.
(11-13)+(-2m+m)+2n(11−13)+(−2m+m)+2n
6 Simplify.
-2-m+2n that is the answer plz Mark me brainliest:)
D. 5 1/8 feet
18 3/4 feet is the same as 18 6/8
23 7/8 feet - 186/8 feet s= 5 1/8 feet
Answer:
Step-by-step explanation:
Answer:
The Inequality representing money she can still spend on her friend birthday gift is .
Jordan can still spend at most $30 on her friends birthday gift.
Step-by-step explanation:
Given:
Total money need to spend at most = $45
Money spent on Yoga ball = $15
We need to find how much money she can still spend on her friend birthday gift.
Solution:
Let the money she can still spend on her friend birthday gift be 'x'.
So we can say that;
Money spent on Yoga ball plus money she can still spend on her friend birthday gift should be less than or equal to Total money need to spend.
framing in equation form we get;
The Inequality representing money she can still spend on her friend birthday gift is .
On solving the the above Inequality we get;
we will subtract both side by 15 using subtraction property of Inequality.
Hence Jordan can still spend at most $30 on her friends birthday gift.
Answer:
8 bags of pretzels
Step-by-step explanation:
Let x represent the number of bags of pretzels Tim buys. We assume he spends exactly $20 on exactly 12 bags of snack food. Then his purchase is ...
1.50x + 2.00(12-x) = 20.00
-0.50x +24.00 = 20.00 . . . eliminate parentheses, collect terms
-0.50x = -4.00 . . . . . . . . . . .subtract 24
x = 8 . . . . . . . . . . divide by -0.50
Tim will buy 8 bags of pretzels.
9514 1404 393
Answer:
A. subtraction
B. division
C. multiplication
D. addition
Step-by-step explanation:
Observe what is done to the variable. Choose the operation that turns the unwanted value into the appropriate identity element.
A. 3.75 is added. To make that value be 0, we subtract 3.75.
B. -3 is multiplied. To make that value be 1, we divide by -3.
C. m is divided by 5. To make that 1/5 multiplier be 1, we multiply by 5.
D. 4 is subtracted. To make that value be zero, we add 4.
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<em>Additional comment</em>
Since subtraction is the same as addition of the opposite, and division is the same as multiplication by the reciprocal, the only two properties we really need are the <em>addition property</em> and <em>multiplication property</em>. Your grader may disagree.
