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JulsSmile [24]
3 years ago
11

Roy driving 582 miles to family reunions she will drive 300 miles by herself the first day the second day Roy and her cousin wil

l share the driving equally how many miles would her cousin Drive
Mathematics
1 answer:
monitta3 years ago
7 0
In the first day she drive by her self 300

The miles remains to the second day

582-300=282

In the second day it will share the driving with her cousin equally

so she will drive 282/2=141 miles and her cousin also 141 miles
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Consider a sphere of radius R > 0. Take two antipodal points A and B on the sphere, and another point C on the sphere. Check
aleksklad [387]

Answer:

To this question; we want to show that if two antipodal points on a sphere were A and B, for any random point C on the sphere, AC is perpendicular to BC?

Step-by-step explanation:

I would proceed by imagining the sphere in a three dimensional Cartesian coordinate system. For example, use a sphere of diameter 2 and let it sit at the origin. Then (0, 0, 1) and (0, 0, -1) are the vector locations of the “north and south poles” of the sphere.

Now choose the vector location of any point on the surface of the sphere. It will have a vector location - we’ll call it (x, y, z). Now the vectors from your point to the two poles are (-x, -y, 1-z) and (-x, -y, -1-z).

Now just form the dot product of those two vectors:

(-x, -y, 1-z) . (-x, -y, -1-z) = x^2 +y^2 + (1-z)*(-1-z)

Now the truth of your claim will be embodied in that dot product being zero:

x^2 + y^2 - (1+z)(1-z) = 0

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x^2 + y^2 + z^2 = 1

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Since R>0 and AC is perpendicular to BC, the <ACB is at right angle.

Please, find attached a simple image to show antipodal points (Two points that makes a diameter) and a point C on the sphere.

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