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mel-nik [20]
3 years ago
7

A pair of equations is shown below: y = 6x + 9 y = 7x + 7 What is the solution to the pair of equations?

Mathematics
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

x=2, y= 21

Step-by-step explanation:

y = 6x + 9

y = 7x + 7

Since both equations are equal to y, we can set them equal to each other

6x+9 = 7x+7

Subtract 6x from each side

6x+9-6x = 7x -6x+7

9 = x+7

Subtract 7 from each side

9-7 = x+7-7

x=2

Now we need to find y

y = 6x+9

y = 6(2) +9

y = 12 +9

y = 21

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parking garage has 5 floors. If 117 cars can be parked on each floor, how many total cars can park in the garage? Drag numbers t
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Step-by-step explanation:

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40x=10x^2+41 <br><br> Identify the number of solutions and their types using the discriminant
nydimaria [60]

Number of solutions: no roots

Type of solution: Not Real

Step-by-step explanation:

We need to identify the number of solutions and their types using the discriminant.

We are given: 40x=10x^2+41\\

Rearranging:

40x-10x^2-41=0\\10x^2-40x+41=0

Discriminant can be found by: b^2-4ac

where b=-40, a=10 and c=41

Putting values:

b^2-4ac\\=(-40)^2-4(10)(41)\\=1600-1640\\=-40\\

So, Discriminant is -40

If the discriminant is less than zero i.e -40 then there are no real roots.

So, Number of solutions: no roots

Type of solution: Not Real

Keywords: discriminant

Learn more about discriminant at:

  • brainly.com/question/8196933
  • brainly.com/question/9328925
  • brainly.com/question/9184197

#learnwithBrainly

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3 years ago
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