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olganol [36]
3 years ago
13

A ______ is a number that is a multiple of two or more numbers

Mathematics
1 answer:
Rufina [12.5K]3 years ago
6 0
Answer: Common multiple
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6y-6y-12y=please help me
Ray Of Light [21]
Hello.

The answer is 

-12y

Combine Like Terms:<span>=<span><span><span>6y</span>+<span>−<span>6y</span></span></span>+<span>−<span>12y</span></span></span></span><span>=<span>(<span><span><span>6y</span>+<span>−<span>6y</span></span></span>+<span>−<span>12y</span></span></span>)</span></span><span>=<span>−<span>12<span>y

Have a nice day</span></span></span></span>
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3 years ago
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Murphy loves pistachio nuts. Every saturday morning, she walks to the market and buy some. Last week, she bought two pounds and
Alexxx [7]

Question is Incomplete, Complete question is given below,

Murphy loves pistachio nuts. Every Saturday morning, she walks to the market and buys some. Last week, she bought two pounds and paid $7.96, and this week she bought only one-half pound and paid $1.99. What the unit rate for pistachio nuts?

Answer:

The unit rate for pistachio nuts is $3.98.

Step-by-step explanation:

Given;

Price of 2 pounds of pistachio nuts = $7.96

We need to find the price of 1 pound of pistachio nuts.

To find the same we will use the unitary method,

Hence ,

Price of 1 pound of pistachio nuts = \frac{\$7.96}{2} = \$3.98

Also given:

Price of half pound of pistachio nuts = $1.99

We need to find the price of 1 pound of pistachio nuts.

To find the same we will use the unitary method,

Hence ,

Price of 1 pound of pistachio nuts = \$1.99\times 2 = \$3.98

Hence, The unit rate for pistachio nuts is $3.98

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3 years ago
The cost of a student ticket tot he school play is 7$ write an equation that correctly relates the total cost, c, for a particul
SVEN [57.7K]
An equation that fit this is c=7s
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3 years ago
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Condense the log equation: 4 log x + log y - 5 log z
Setler [38]

Answer:

The condensed log equation is: \log{\frac{x^4y}{z^5}}

Step-by-step explanation:

We use these following logarithm properties to solve this question:

a\log{x} = \log{x^a}

\log{a} + \log{b} = \log{ab}

\log{a} - \log{b} = \log{\frac{a}{b}}

In this question:

4\log{x} = \log{x^4}

5\log{5} = \log{z^5}

So

4\log{x} + \log{y} - 5\log{z}

Becomes:

\log{x^4} + \log{y} - \log{z^5}

Now applying the addition and subtraction properties, we have:

\log{\frac{x^4y}{z^5}}

The condensed log equation is: \log{\frac{x^4y}{z^5}}

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3 years ago
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2 please pick me!!!!
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