Step-by-step explanation:
ED is greater than BC
the line from B to ED ^ (which i drew ) the point it touches ED name it X. so EX will be 2 ( ED-BC)(6-4).
then u have a triangle. EX, XB and EB.
you have length of EX(2) and u have hypotenuse. so u can calculate XB using Pythagoras theorem.
15.1²=2²+XB²
15.1²-2²=XB²
224.01=XB²
XB=14.97
since XB and DC are parallel ( a rectangle is forming XBCD) so DC is also 14.97
The line equation is given by
where <em>m </em>is the slope and <em>b </em>is the interception with <em>Y-axis</em>
Answer:
X= 5
Explanation (Steps):
<u>Step 1: Simplify both sides of the equation.</u>
−3.4(x−2)=9.8−4x
(−3.4)(x)+(−3.4)(−2)=9.8+−4x(Distribute)
−3.4x+6.8=9.8+−4x
−3.4x+6.8=−4x+9.8
<u>Step 2: Add 4x to both sides.</u>
−3.4x+6.8+4x=−4x+9.8+4x
0.6x+6.8=9.8
<u>Step 3: Subtract 6.8 from both sides.</u>
0.6x+6.8−6.8=9.8−6.8
0.6x=3
<u>Step 4: Divide both sides by 0.6.</u>
0.6x0.6=3/0.6
x=5
4x10^7 The number of zeros the given number has would be the exponent
The x intrercepts is where the function crosses the x axis; In other words, it is where the output of the function is 0.
In a quadratic, you can start by factoring, if it’s unable to be factored then use the quadratic formula. Also, it is good to use the discriminate.
D= Discrimminate
D>0 2 real solutions
D=0 1 real solution
D<0 2 imaginary solutions.
The discrimminate is the equation/expression under the radical of the quadratic formula. With this formula, it’s not factorable. Using the discriminate it is also seen, as you’ll get a negative in the square root. This is imagenary because you cannot take the root of a negative value, which is why “i” is used to represent the square root of negative one.
