Answer:
a) x1 = 6 and x2 = -2
b) -2
Step-by-step explanation:
a)
To find the roots of the quadratic equation, we can use the Bhaskara's formula:
Delta = b^2 - 4ac
Delta = (-4)^2 - 4*1*(-12) = 64
sqrt(Delta) = 8
x1 = (-b + sqrt(Delta)) / 2a
x1 = (4 + 8) / 2
x1 = 6
x2 = (-b - sqrt(Delta)) / 2a
x2 = (4 - 8) / 2
x2 = -2
b)
The roots are 6 and -2, so the smaller root is -2
Answer:
(4×-3)(2x-1)
Step-by-step explanation:
8x²-10x+3
8x²-4x-6x+3
4x(2x-1)-3(2x-1)
(4×-3)(2x-1)
Answer:
Surface area = 10.7 in.²
Step-by-step explanation:
Surface Area of triangular pyramid = BA + P*L
Base Area (BA) = ½*nh
b = 2 in.
h = 1.7 in.
BA = ½*2*1.7 = 1.7 in.²
Perimeter (P) = 2 + 2 + 2 = 6 in.
Slant height (L) = 3 in.
Plug in the values
Surface Area = 1.7 + ½*6*3
Surface area = 10.7 in.²
