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erastova [34]
3 years ago
11

Find the equation of the line that passes through the following lines points (0,-1) and (3,12).​

Mathematics
1 answer:
Temka [501]3 years ago
8 0

Answer:

y=13/3x-1

Step-by-step explanation:

k=(y2-y1) /(x2-x1)

A(0,-1) x1=0,y1=-1

B(3,12) x2=3, y2=12

k=(12-(-1))/(3-0)

k=(12+1)/3

k=13/3

y-y1=k(x-x1)

y-(-1)=13/3(x-0)

y+1=13/3*x

y=13/3*x-1

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Jenna and Becca were both selling cookies door to door. Jenna sold 8 boxes of cookies for every 3 boxes of cookies Becca sold. C
LenaWriter [7]
Answer:
Jenna sold 280 boxes, Becca sold 105 boxes.

Step-by-step explanation:
For every 3 boxes B sold, J sold 8 boxes and ended with a total of 385 boxes sold.
3b+8j=385
From how the question is asked, we can assume that each round of sales would equal 11 total sales. (3b+8j=11)
Knowing the sales take place in intervals of 11, we can solve the problem by doing 385/11.
385/11=35
Finally, with 35 rounds of sales happening and knowing Jenna sells 8 while Becca sells 3 at each one, all that's left to do is multiply.
8x35=280
3x35=105
To be sure we can check our answer by adding them together, 280+105=385.
4 0
1 year ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
2 years ago
Can someone help pls​
finlep [7]
It’s C like the guy said
4 0
3 years ago
How to write repeating 3.01 as a mixed number
stepan [7]
3.010101.. = 3 + 0.010101... = 3 + 1/(100 - 1) = 3 + 1/99 = 3 1/99
7 0
3 years ago
Suppose the CPI has a value of 225.3 exactly one year ago, and the current value of this index is 231.16, a rise of 5.86 points.
sertanlavr [38]

Answer:

2.6%

Step-by-step explanation:

Given the current CPI = 231.56

Previous CPI (CPI a year ago) = 225.3

Rate of inflation over the past year = current CPI - previous CPI/previous CPI × 100%

Rate of inflation = 231.56-225.3/225.3 × 100%

5.86/225.3× 100%

= 2.6%

Rate of inflation over the past year will be 2.6%

4 0
3 years ago
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