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3 years ago

Find the equation of the line that passes through the following lines points (0,-1) and (3,12).

Mathematics

1 answer:

Temka [501]3 years ago

8 0

Answer:

y=13/3x-1

Step-by-step explanation:

k=(y2-y1) /(x2-x1)

A(0,-1) x1=0,y1=-1

B(3,12) x2=3, y2=12

k=(12-(-1))/(3-0)

k=(12+1)/3

k=13/3

y-y1=k(x-x1)

y-(-1)=13/3(x-0)

y+1=13/3*x

y=13/3*x-1

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3 years ago

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Lunna [17]

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3 years ago

WILL MARKBRANLIEST ...

MA_775_DIABLO [31]

Make ratios.

12/16: 15/x

cross multiply

12(x) = 12x
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12x = 240

isolate the x, divide 12 from both sides

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x = 20

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3 years ago

Find the y-intercept for the line represented by this equation.

sashaice [31]

Answer:

A) (0,0)

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1.) graph the equation, 3x+2y = x+y

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3 years ago

Find the equation of the line that passes through the following lines points (0,-1) and (3,12).​

Find the equation of the line that passes through the following lines points (0,-1) and (3,12).