Find the equation of the line that passes through the following lines points (0,-1) and (3,12).
1 answer:
Answer:
y=13/3x-1
Step-by-step explanation:
k=(y2-y1) /(x2-x1)
A(0,-1) x1=0,y1=-1
B(3,12) x2=3, y2=12
k=(12-(-1))/(3-0)
k=(12+1)/3
k=13/3
y-y1=k(x-x1)
y-(-1)=13/3(x-0)
y+1=13/3*x
y=13/3*x-1
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