Which part of this graph shows a nonlinear relationship?
1 answer:
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We can start from the given line's coefficients and translate the line from the origin to the given point.
4(x -(-2)) -(y -3) = 0
4x +8 -y +3 = 0
The equation of the desired line is ...
4x -y = -11
_____
For standard form line ax+by=c, any parallel line will have only a different value of c. For c=0, the line goes through the origin (0, 0). To make it go through point (h, k) we can write it as
a(x-h) +b(y-k) = 0
which is completely equivalent to
ax +by = ah +bk
4(x -(-2)) -(y -3) = 0
4x +8 -y +3 = 0
The equation of the desired line is ...
4x -y = -11
_____
For standard form line ax+by=c, any parallel line will have only a different value of c. For c=0, the line goes through the origin (0, 0). To make it go through point (h, k) we can write it as
a(x-h) +b(y-k) = 0
which is completely equivalent to
ax +by = ah +bk
Answer:
d = 48t will represent the distance 'd' traveled in 't' hours.
Step-by-step explanation:
Jason leaves Detroit at 2:00 PM and passes through Ann Arbor at 2:50 PM which is 40 mi distant from Detroit.
Speed during this journey was constant.
Jason traveled 40 mi in 50 minutes or hours from Detroit to Ann Arbor.
By the formula,
Speed =
Speed =
= 48 mi per hour
If he travels 'd' miles in 't' hours then by the formula of speed,
48 =
d = 48t