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Lesechka [4]
3 years ago
8

The average blue whale gains weight at a constant rate each day during its first six months of life the relationship between the

average blue whales weight in tons w and its age in days d for the first six months of its life can be modeled by the function w=0.1d+3 based on this relationship which statement is not true about blue whales
A. the average blue whale weighs 3 tons at birth
B. when the average blue whale is 5 days old it weighs 20 tons
C. the average blue whale gains 0.1 ton per day during its first six month of life
D. when the average blue whale weighs 18 tons it is 150 years old
Mathematics
1 answer:
pickupchik [31]3 years ago
6 0
The answer to your question is B
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-13 + 24-46-( - 20 ) =
Naddik [55]

Answer

-15

Step-by-step explanation:

-13 +24=11

11-46=-35

-35+20=-15

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3 years ago
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Steven is researching prices on living room sofas in order to determine what a typical sofa costs. Which statement correctly exp
Hatshy [7]

Answer:

the answer is c because it can be either greatly increased or decreased

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3 years ago
Write the first four terms of the sequence:<br> a = 2<br> an = a(n-1) + 4
eduard

We have sequence equation a_n=a(n-1)+4.

In this case n is a natural number (1, 2, 3, ...).

So start inserting and computing value of a_n given that you know the value of n and a.

a_1=2(1-1)+4=4 (first term)

a_2=2(2-1)+4=6 \\a_3=2(3-1)+4=8 \\a_4=2(4-1)+4=10

Hope this helps.

3 0
3 years ago
Ron has 25 coins with a total value of $ 4.30 . the coins are dimes and quarters. how many of each coin does he have?
Gwar [14]
25=d+q
4.30= .1d + .25q

25=d+q
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4 0
3 years ago
Find the derivative of the following. please show the steps when you answer :1) f(x) = 8xe^x2) y= 5xe^x^43) f(x)= x^8+5/x4) f(t)
borishaifa [10]

Answer:

Since,

\frac{d}{dx}x^n = nx^{n-1}

\frac{d}{dx}(f(x).g(x)) = f(x).\frac{d}{dx}(g(x)) + g(x).\frac{d}{dx}(f(x))

\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{g(x).f'(x) - f(x) g'(x)}{(g(x))^2}

1) y = 8x e^x

Differentiating with respect to x,

\frac{dy}{dx}=8( x \times e^x + e^x) = 8(xe^x + e^x) = 8e^x(x+1)

2) y = 5x e^{x^4}

Differentiating w. r. t x,

\frac{dy}{dx}=5(x\times 4x^3 e^{x^4}+e^{x^4})=5e^{x^4}(4x^4+1)

3) y = x^8 + \frac{5}{x^4}

Differentiating w. r. t. x,

\frac{dy}{dx}=8x^7 - \frac{5}{x^5}\times 4 = 8x^7 - \frac{20}{x^5}=\frac{8x^{12}-20}{x^5}

4) f(t) = te^{11}-6t^5

Differentiating w. r. t. t,

f'(t) = e^{11} - 30t^4

5) g(p) = p\ln(2p+3)

Differentiating w. r. t. p,

g'(p) = p\frac{1}{2p+3}(2) + \ln(2p+3) = \frac{2p}{2p+3}+\ln(2p+3)

6) z = (te^{6t}+e^{5t})^7

Differentiating w. r. t. t,

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7) w =\frac{2y + y^2}{7+y}

Differentiating w. r. t. y,

\frac{dw}{dy} = \frac{(7+y)(2+2y)-(2y+y^2)}{(7+y)^2} = \frac{14 + 2y + 14y +2y^2 - 2y - y^2}{(7+y)^2}=\frac{14+14y+y^2}{(7+y)^2}

7 0
3 years ago
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