Question

A golf association sets performance standards for golf balls. For​ example, the initial velocity of the ball may not exceed 250 feet per second when measured by an apparatus approved by the association. Suppose a manufacturer introduces a new kind of ball and provides a randomly selected sample of balls for testing. Based on the mean speed in the​ sample, the association comes up with a​ P-value of 0.38. Explain in this context what the 38​% represents. Upper H 0​: equals 250 ​ft/sec Upper H Subscript Upper A​: greater than 250 ​ft/sec

Answer 1

Answer:

In this context 38% represents that if the mean speed of ball is 250 ft/sec, then there is 34% chance of obtaining a similar or more extreme value related to test statistics.

Step-by-step explanation:

We are given that the initial velocity of the ball may not exceed 250 feet per second when measured by an apparatus approved by the association.

Based on the mean speed in the​ sample, the association comes up with a​ P-value of 0.38.

Let $\mu$ = mean speed of the ball

So, Null Hypothesis, $H_0$ : $\mu$ = 250 ​ft/sec

Alternate Hypothesis, $H_A$ : $\mu$ > 250 ft/sec

Now, the P-value given to us is 0.38.

P-value basically tells us the exact percentage where our test statistics lie. Also, it is the probability of obtaining the value that is more extreme, given that null hypothesis is true,

So, in this context 38% represents that if the mean speed of ball is 250 ft/sec, then there is 34% chance of obtaining a similar or more extreme value related to test statistics.