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NeX [460]
3 years ago
12

Drag each statement to the correct category. Classify the sentences based on whether they are or are not statements. Prime numbe

rs are easier to count. Irrational numbers can be written as fractions. Natural numbers can be negative. Addition is the simplest mathematical operation. Equilateral triangles are quicker to construct than scalene triangles. The set of real numbers is infinite.
statement not a statement
Mathematics
1 answer:
Archy [21]3 years ago
6 0

Answer:

1. Prime numbers are easier to count. (Not a statement)

2.Irrational numbers can be written as fractions. (Statement)

3. Natural numbers can be negative. (Statement)

4.  Addition is the simplest mathematical operation. (Not a Statement)

5. Equilateral triangles are quicker to construct than scalene triangles. (Not a statement)

6. The set of real numbers is infinite. (Statement)

i hope it will help you!

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50 POINTS!!!!!!!
stira [4]

Answer:

For this transition of equations, the graph of g(x) will be translated left 2 units with respect to the graph of f(x), so your answer choice will be A.

Step-by-step explanation:

In this equation, g(x) is changed by adding 2 and closing part of the equation in parenthases, this results in the translation 2 units left, which can be proven by a graph and my answer.

3 0
3 years ago
A population has a mean of 200 and a standard deviation of 50. Suppose a sample of size 100 is selected and x is used to estimat
zmey [24]

Answer:

a) 0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b) 0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 200, \sigma = 50, n = 100, s = \frac{50}{\sqrt{100}} = 5

a. What is the probability that the sample mean will be within +/- 5 of the population mean (to 4 decimals)?

This is the pvalue of Z when X = 200 + 5 = 205 subtracted by the pvalue of Z when X = 200 - 5 = 195.

Due to the Central Limit Theorem, Z is:

Z = \frac{X - \mu}{s}

X = 205

Z = \frac{X - \mu}{s}

Z = \frac{205 - 200}{5}

Z = 1

Z = 1 has a pvalue of 0.8413.

X = 195

Z = \frac{X - \mu}{s}

Z = \frac{195 - 200}{5}

Z = -1

Z = -1 has a pvalue of 0.1587.

0.8413 - 0.1587 = 0.6426

0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b. What is the probability that the sample mean will be within +/- 10 of the population mean (to 4 decimals)?

This is the pvalue of Z when X = 210 subtracted by the pvalue of Z when X = 190.

X = 210

Z = \frac{X - \mu}{s}

Z = \frac{210 - 200}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

X = 195

Z = \frac{X - \mu}{s}

Z = \frac{190 - 200}{5}

Z = -2

Z = -2 has a pvalue of 0.0228.

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

7 0
3 years ago
Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.
gavmur [86]

The required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

<h3>What is integer?</h3>

An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Zero is not a fraction or decimal of any number. It is neither positive nor negative.

Given:

Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.

According to given question we have

2-digit numbers are the numbers that have two digits and they start from the number 10 and end on the number 99.

Starting at 12 going up the two digit numbers even numbers less than 25 that do not contain the digit 0.

12,14,16,18,22,24

Therefore, the required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

Learn more details about integer here:

brainly.com/question/15276410

#SPJ1

4 0
1 year ago
My Christmas present to you​
Temka [501]

Answer:

Step-by-step explanation:

if you need help let me know

5 0
2 years ago
Read 2 more answers
Victoria has $200 of her birthday gift money saved at home, and the amount is modeled by the function h(x) = 200. She reads abou
svlad2 [7]

Solution :

Amount of money Victoria has = $200

The amount modelled by function = h(x) = 200

According to the function,

s(x) = (1.05)x - 1

It means that the total amount of the interest that Victoria will receive s(x) is equal to original amount of $200 which multiplied by the rate of interest (1.05) and then multiplied by the time that Victoria keeps the money in the bank (x) minus 1.

4 0
2 years ago
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