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3 years ago

If you wanted to reduce the 8x6 rectangle by a ratio of 1/4 what would the dimensions of the new rectangle be

Mathematics

1 answer:

Sveta_85 [38]3 years ago

8 0

The answer would be...2 x 1 1/2....sorry if I'm wrong! :)

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A number has 2,5 and 7 as its prime factors. what are the four smallest values it and take

MA_775_DIABLO [31]

Answer:

70, 140, 280, 350

Step-by-step explanation:

Obviously, it must have the factors 2, 5, 7 as a minimum, so the smallest value is 2×5×7 = 70.

Any of these primes can be added to the product. In increasing order, the smallest additional factors will be 2, 4, 5, 7, 8, 10, ...

So, the four smallest numbers with prime factors of 2, 5, and 7 are ...

70 = 2·5·7

140 = 2²·5·7

280 = 2³·5·7

350 = 2·5²·7

3 0

3 years ago

PLEASEEEEEEEEEE HELPPPPPPPPPPP

ankoles [38]

Answer:

I would just guess, but if i were to actually think about it, i would think C. I hope it helps, and blame it on me if you fail.

Step-by-step explanation:

8 0

3 years ago

A=1/4 and b=6.<br><br> −8ab=

podryga [215]

Answer:

When $a=\frac{1}{4}$ and $b=6$ :

$-8ab=-12$

Step-by-step explanation:

-8ab can be seen as -8×a×b. Insert the given values:

$-8*\frac{1}{4} *6$

Simplify multiplication from left to right:

$-8*\frac{1}{4} \\\\\frac{-8}{1} *\frac{1}{4} =\frac{-8}{4} =-2$

Insert and solve:

$-2*6=-12$

:Done

3 0

3 years ago

A box contains 3 green marbles, 5 blue marbles, and 7 red marbles. Three marbles are selected at random from the box, one at a t

USPshnik [31]

Answer:

The probability is $P(K) = \frac{ 28 }{195}$

Step-by-step explanation:

From the question we are told that

The number of green marbles is $n_g = 3$

The number of red marbles is $n_b = 5$

The number of red marbles is $n_r = 7$

Generally the total number of marbles is mathematically represented as

$n_t = n_r + n_g + n_ b$

$n_t = 7 + 3 + 5$

$n_t = 5$

Generally total number of marbles that are not red is

$n_k = n_g + n_ b$

=> $n_k = 3 + 5$

=> $n_k = 8$

The probability of the first ball not being red is mathematically represented as

$P(r') = \frac{n_k}{n_t}$

=> $P(r') = \frac{ 8}{15}$

The probability of the second ball not being red is mathematically represented as

$P(r'') = \frac{n_k - 1}{n_t -1}$

=> $P(r'') = \frac{ 8 -1 }{15-1}$ (the subtraction is because the marbles where selected without replacement )

=> $P(r'') = \frac{ 7 }{14}$

The probability that the first two balls is not red is mathematically represented as

$P(R) = P(r') * P(r'')$

=> $P(R) = \frac{ 8}{15} * \frac{ 7 }{14}$

=> $P(R) = \frac{ 8 }{30}$

The probability of the third ball being red is mathematically represented as

$P(r) = \frac{n_r}{ n_t -2}$ (the subtraction is because the marbles where selected without replacement )

$P(r) = \frac{7}{ 15 -2}$

=> $P(r) = \frac{7}{ 13}$

Generally the probability of the first two marble not being red and the third marble being red is mathematically represented as

$P(K) = P(R) * P(r)$

$P(K) = \frac{ 8 }{30} * \frac{7}{ 13}$

=> $P(K) = \frac{ 28 }{195}$

6 0

3 years ago

HELPP !!!!!!!!!!!!!!!!!!!!!!!

Umnica [9.8K]

I cannot see the picture to good

3 0

3 years ago