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Jlenok [28]
3 years ago
15

Drag each label to the correct location on the table.

Mathematics
1 answer:
k0ka [10]3 years ago
7 0
Idk figure it out.. sorry
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Which shows the list of numbers in order from least to greatest?
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The answer is A.-2, |-4/5|, |-1|, |3.5|, |-4.2|

Step-by-step explanation:

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3 years ago
Evaluate t-7 for t =20
Luda [366]

Answer:

The answer is 14

Step-by-step explanation:

t - 7 ; t = 20

20 - 7 = 14

Thus, The answer is 14

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2 years ago
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Ken bakes several batches of cookies throughout the day for his bakery. He records the number of cookies, in dozens, that are in
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<h3>✽ - - - - - - - - - - - - - - -  ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ The equation would have to be y = 4/3 x + 4 because the y intercept is 4 and the gradient is positive.

The two correct statements are the first and last ones.

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3 0
3 years ago
If you have 24 dozen Shamrock cookies horseshoe cookies mint cupcakes and you sold four times as many cupcakes as cookies and th
Elden [556K]

Answer:

144

Step-by-step explanation:

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3 0
3 years ago
A top-loading washing machine has a cylindrical basket that rotates about a vertical axis. The basket of one such machine starts
damaskus [11]

Answer:

n_{tot}=44rev

Step-by-step explanation:

In order to solve this problem we can make use of the following formula:

\theta=(\frac{\omega_{f}+\omega_{0}}{2})t

where θ is the total angle the basket has turned, ω is the angular velocity and t is the time.

Generally theta is written in radians and omega is written in radians per second. Now, since the revolutions are directly related to the radians and they want us to write our answer in revolutions, we can directly use the provided speeds in the formula, so we can rewrite it as:

n=(\frac{f_{f}+f_{0}}{2})t

where n represents the number of revolutions and f is the frequency at which the basket is turning.

The movement of the cylindrial basket can be split in two stages, when it accelerates and when it decelerates. So let's analye the first stage:

n=(\frac{4rev/s+0}{2})(9s)=18rev

and now let's analyze the second stage, where it decelerates, so we get:

n=(\frac{0rev/s+4rev/s}{2})(13s)=26rev

So now that we know how many revolutions the cylindrical basket will take as it accelerates and as it decelerates we can add them to get:

n=18rev+26rev=44rev

So the basket will turn a total of 44 revolutions during this 22s interval.

3 0
3 years ago
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