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Jlenok [28]
3 years ago
15

Drag each label to the correct location on the table.

Mathematics
1 answer:
k0ka [10]3 years ago
7 0
Idk figure it out.. sorry
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Two coins and a number cube are tossed at the same time. What is the approximate probability that the coins show different sides
Wewaii [24]
0.17
tell me if i am right

7 0
3 years ago
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Find the 8th term for the series 2, 8, 32, 128, … <br> A. 8192<br> B. 16384<br> C. 6784<br> D. 32768
GenaCL600 [577]

Answer:32,768

2*4=8*4=32*4=128

So we have to multiply by 4

128*4=512 5th term

512*4=2048 6th term

2048*4=8192 7th term

8192*4=32768 last term

7 0
3 years ago
A group conducted a poll of 2083 likely voters just prior to an election. The results of the survey indicated that candidate A w
mart [117]

Answer:

With the given margin of error its is possible that candidate A wins and candidate B loses, and it is also possible that candidate B wins and candidate A loses. Therefore, the poll cannot predict the winner and this is why race was too close to call a winner.

Step-by-step explanation:

A group conducted a poll of 2083 likely voters.

The results of poll indicate candidate A would receive 47​% of the popular vote and and candidate B would receive 44​% of the popular vote.

The margin of error was reported to be 3​%

So we are given two proportions;

A = 47%

B = 44%

Margin of Error = 3%

The margin of error shows by how many percentage points the  results can deviate from the real proportion.

Case I:

A = 47% + 3% = 50%

B = 44% - 3% = 41%

Candidate A wins

Case II:

A = 47% - 3% = 44%

B = 44% + 3% = 47%

Candidate B wins

As you can see, with the given margin of error its is possible that candidate A wins and candidate B loses, and it is also possible that candidate B wins and candidate A loses. Therefore, the poll cannot predict the winner and this is why race was too close to call a winner.

5 0
3 years ago
Eliza started her savings account with $100. Each month she deposits $25 into her account. Determine the average rate of change
Afina-wow [57]
First, lets create a equation for our situation. Let x be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>f(x)=25x+100
<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is: \frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1} }. So lets replace the values in our formula to find the average of our function:
\frac{25(10)+100-[25(2)+100]}{10-2}
\frac{350-150}{8}
\frac{200}{8}
25

We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
6 0
3 years ago
A.63<br> B.54<br> C.99<br> D.126
Neporo4naja [7]

Answer:

C

Step-by-step explanation:

Area = (8 + 14) x 1/2 x 9

Area = 22 x 1/2 x 9

Area = 11 x 9

Area = 99

<em>Hope that helps!</em>

<em>-Sabrina</em>

6 0
3 years ago
Read 2 more answers
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