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3 years ago

PLEASE HELP ASAP QUESTIONS ARE IN PICTURE

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

5 0

Answer:

1. Last option

2. third option

Step-by-step explanation:

1. Each term is formed by multiplying the previous one by 3

so its 729, 2187

2. Working from right to left we multiply by 5 so its 500.

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You play video games online. When you sign up with the game site, you get 200 points. You earn 20 more points for each hour that

Savatey [412]

500 = 200 + 20h is our equation.
Subtract 200 from both sides
300 = 20h
Divide by 20
300/20 = 15.
It will take 15 hours to get 500 points.
Hope this helps!

8 0

3 years ago

Read 2 more answers

2. f(x)=4x+1 and g(x)=x2−4x−5, find (g◦f)(4).

Goryan [66]

Answer:

(g · f)(4) = 45

Step-by-step explanation:

f(x)=4x+1

g(x)=x² - 4x- 5

(g · f)(x) = 4(x² - 5) + 1

(g · f)(4) = 4(4² - 5) + 1

Following pemdas

(g · f)(4) = 4(16 - 5) + 1

(g · f)(4) = 4(11) + 1

(g · f)(4) = 44 + 1

(g · f)(4) = 45

8 0

2 years ago

Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)

Fantom [35]

Answer:

Given: $\sin(x) = (4/5)$ .

Assuming that $0 < x < 90^{\circ}$ , $\cos(x) = (3/5)$ while $\tan(x) = (4/3)$ .

Step-by-step explanation:

By the Pythagorean identity $\sin^{2}(x) + \cos^{2}(x) = 1$ .

Assuming that $0 < x < 90^{\circ}$ , $0 < \cos(x) < 1$ .

Rearrange the Pythagorean identity to find an expression for $\cos(x)$ .

$\cos^{2}(x) = 1 - \sin^{2}(x)$ .

Given that $0 < \cos(x) < 1$ :

$\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}$ .

Hence, $\tan(x)$ would be:

$\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}$ .

7 0

2 years ago

Please provide the working outs as well as the answer. Many thanks

lana [24]

$\dfrac{3w-5}{2}=w-3\ \ \ |multiply\ both\ sides\ by\ 2\\\\\not2^1\cdot\dfrac{3w-5}{\not2_1}=2\cdot w-2\cdot3\\\\3w-5=2w-6\ \ \ |add\ 5\ to\ both\ sides\\\\3w-5+5=2w-6+5\\\\3w=2w-1\ \ \ \ |subtract\ 2w\ from\ both\ sides\\\\3w-2w=2w-2w-1\\\\\boxed{w=-1}$

4 0

4 years ago

Use the discriminant to describe the roots of each equation. Then select the best description. 2 = x2 + 5x. A) Double root B) Re

fredd [130]

$\bf 2=x^2+5x\implies 0=x^2+5x-2\\\\\\\qquad \qquad \qquad \textit{discriminant of a quadratic}\\\\\\0=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+5}x\stackrel{\stackrel{c}{\downarrow }}{-2}~~~~~~~~\stackrel{discriminant}{b^2-4ac}=\begin{cases}0&\textit{one solution}\\positive&\textit{two solutions}\\negative&\textit{no solution}\end{cases}\\\\\\(5)^2-4(1)(-2)\implies 25+8\implies 33$

so we have a 33, namely two real solutions for that quadratic.

usually that number goes into a √, if you have covered the quadratic formula, you'd see it there, namely that'd be equivalent to √(33), now 33 is a prime number, and √(33) is yields an irrational value, specifically because a prime number is indivisible other than by itself or 1.

so 33 can only afford us two real irrational roots.

3 0

3 years ago