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Whitepunk [10]
3 years ago
8

the area of a rectangular field is x^2-x-72m^2. the length of the field is x+8m. what is the width of the field in meters?

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
7 0
So first off, remember the formula for the area of a rectangle. it's length time width right? or, you could think that A= 2 things multiplied together. how can we simplify x^2 - x -72 to equal two things multiplied together? well, we can factor it! We know that one of the factors is x+8 right? so what's the other factor? it would be x-9. so, we know width is x-9. I'm not sure if you need an actual value for width. if so, I could probably go further.
Kamila [148]3 years ago
5 0

Answer:

w=x-9

Step-by-step explanation:

It is given that area of the rectangle is \left (x^{2} -x-72\right )\:m^{2} and length of the rectangle is (x+8) \:m

We know that area of rectangle is length\timeswidth

We have, l\times b=x^{2}-x-72

w=\frac{x^{2}-x-72}{x+8} \:\:\left [ \because l=x+8 \right ]

w=\frac{x^{2}-9x+8x-72}{x+8}

w=\frac{x\left ( x-9 \right )+8\left ( x-9 \right )}{x+8}

w=\frac{\left ( x+8 \right )\left ( x-9 \right )}{x+8}

w=x-9

Hence, width of the rectangle is w=(x-9)\,m

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