Question

the area of a rectangular field is x^2-x-72m^2. the length of the field is x+8m. what is the width of the field in meters?

Answer 1

So first off, remember the formula for the area of a rectangle. it's length time width right? or, you could think that A= 2 things multiplied together. how can we simplify x^2 - x -72 to equal two things multiplied together? well, we can factor it! We know that one of the factors is x+8 right? so what's the other factor? it would be x-9. so, we know width is x-9. I'm not sure if you need an actual value for width. if so, I could probably go further.

Answer 2

Answer:

$w=x-9$

Step-by-step explanation:

It is given that area of the rectangle is $\left (x^{2} -x-72\right )\:m^{2}$ and length of the rectangle is $(x+8) \:m$

We know that area of rectangle is length$\times$width

We have, $l\times b=x^{2}-x-72$

$w=\frac{x^{2}-x-72}{x+8} \:\:\left [ \because l=x+8 \right ]$

$w=\frac{x^{2}-9x+8x-72}{x+8}$

$w=\frac{x\left ( x-9 \right )+8\left ( x-9 \right )}{x+8}$

$w=\frac{\left ( x+8 \right )\left ( x-9 \right )}{x+8}$

$w=x-9$

Hence, width of the rectangle is $w=(x-9)\,m$