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MA_775_DIABLO [31]
3 years ago
11

Approximately 19.7 million African-American voted in the presidential election with almost 3 million more female than male. What

percent of African-America voted if United States of American is about 28.7 million?
Mathematics
1 answer:
9966 [12]3 years ago
5 0

Step-by-step explanation:

the answer would be 64 became yeah 64 is the andwer

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two years of local internet service cost $685 including the installation fee of $85 what is the monthly fee?
zimovet [89]
2 years is the same as 24 months, so the equation would be:
685 = 24x + 85, where x is the monthly fee.
600 = 24x
600/24 = x
x = 25
The monthly fee is $25.
7 0
2 years ago
Read 2 more answers
Find the equation of the linear function represented by the table below in slope intercept form.
grigory [225]

Answer:

y = -3x - 2

Step-by-step explanation:

slope (m) = (-8 - -5) / (2 - 1)   ... difference of y/difference of x

m = -3

y = mx + b

y = -3x + b

for (3,-11)    b = y + 3x = -11 + 3x3 = -2

equation: y = -3x - 2

5 0
3 years ago
Find the value of sin(a/2) if cosa= 12/13<br>​
daser333 [38]

Answer: sin\frac{a}{2} = ± \frac{1}{\sqrt{26} }

Step-by-step explanation:

We very well know that,

cos2A=1−2sin²A

⟹ sinA = ±\sqrt{(1-} \frac{cos2A}{2} )

As required,  set A = \frac{a}{2}   &   cos a=  \frac{12}{13}    ,thus we get

sin \frac{a}{2} =± \sqrt{\frac{1-cos a}{2} }  

∴ sin\frac{a}{2} =±\sqrt{\frac{1-\frac{12}{13} }{2} } = ± \frac{1}{\sqrt{26} }

   since ,360° < \frac{a}{2} <450°

             ,180° < \frac{a}{2} <225°

Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

   

5 0
2 years ago
What is the gcf of 15 and 10
Zielflug [23.3K]
The gcf of 15 and 10 is 5
7 0
3 years ago
Read 2 more answers
The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0
2 years ago
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