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kirza4 [7]
2 years ago
8

Samantha and Matt are each saving for new bikes. So far, Samantha has saved $15 and can earn $2 per hour for babysitting. Matt h

as saved $3 and can earn $4 per hour working at his family's restaurant. After how many hours of work will Samantha and Matt have earned the same amount?
Mathematics
1 answer:
Sophie [7]2 years ago
7 0

Answer:

  • 6 hours

Step-by-step explanation:

<u>We know that:</u>

  • Samantha = 15 + 2x
  • Matt = 3 + 4x
  • Samantha = Matt
  • [x = Number of hours]

<u>Solution:</u>

  • 15 + 2x = 3 + 4x
  • => 15 - 3 = -2x + 4x
  • => 12 = 2x
  • => x = 6

Hence, after 6 hours of work, Samantha and Matt will have the same amount.

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What is 97.356 in base ten numerals
nadya68 [22]
97.356

<span>ninety seven and three hundred fifty six <span>thousandths</span></span>

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Is 28 cups greater or less than 14 Pints
marissa [1.9K]
Short answer: NO.

28 cups is exactly equal to 14 pints. (There are 2 cups per pint.)
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Zachary used the calculations shown to find how much he would spend on 16 ounces of pistachios.
maw [93]

Answer:

He made a math error

Step-by-step explanation:

6 ounces of pistachios cost $7.50

take 7.50 / 6=1.25 per ounce  ( not .80 per ounce)

Then 1.26 * 16 = 20.00 for 16 ounces

8 0
3 years ago
A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.
Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

t=\sqrt{\frac{2h}{a}} ,where h=height of release

a=acceleration

a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}

Where I=moment of inertia

a for hoop

a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}

a=\frac{g\sin \theta }{2}

a for Uniform solid cylinder

a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}

a=\frac{2g\sin \theta }{3}

a for spherical shell

a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}

a=\frac{3g\sin \theta }{5}

a for Uniform Solid

a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}

a=\frac{5g\sin \theta }{7}

time taken will be inversely proportional to the square root of acceleration

t_1=k\sqrt{2}=1.414k

t_2=k\sqrt{\frac{3}{2}}=1.224k

t_3=k\sqrt{\frac{5}{3}}=1.2909k

t_4=k\sqrt{\frac{7}{5}}=1.183k

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

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3 years ago
Which expression is equivalent to
mojhsa [17]

First choice: m^32n^16

Hope this helps!

6 0
4 years ago
Read 2 more answers
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