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snow_tiger [21]
4 years ago
10

F(x) =2x^2+4x+5 Find: f(a)

Mathematics
1 answer:
MA_775_DIABLO [31]4 years ago
5 0

Answer:

F(a) =2a^2+4a+5

Step-by-step explanation:

just put x= a

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Help me! pleaze help me to do this....give me a step by step answer ..please...
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3 0
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Please Help!!
LuckyWell [14K]

the discriminant is:

D = (-1)^2 - 4*(-2)*6 = 49

We have a positive discriminant, which means that we have two real solutions.

<h3>How to find the discriminant?</h3>

For the general quadratic equation, the discriminant is:

a*x^2 + b*x + c = 0

The discriminant is:

D = b^2 - 4ac

In this case, the quadratic equation is:

6*x^2 - x - 2 = 0

Then we have:

a = 6, b = -1, c = -2

Replacing that in the discriminant equation:

D = (-1)^2 - 4*(-2)*6 = 49

We have a positive discriminant, which means that we have two real solutions.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

#SPJ1

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2 years ago
A customer's stock value seems to be rising exponentially. The equation for
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3 years ago
What is the equation of a line that its parallel to -3x+4y=4 and passes through the point (4,0)?
anzhelika [568]

Answer:

y=3/4x-3

Step-by-step explanation:

Okay so to be parallel to an equation of another line, the line must have the same slope but a different y-intercept. First, you need to find the slope of the equation -3x+4y=4. The equation must be in y=mx+b format, so you first move -3x to the right by adding it on both sides, leaving you with 4y=3x+4. Next, you divide 4y by 4 in order to isolate y and do that on the other side. Now, you have y=3/4x+1.

To find the equation of the new line, you must put the point and slope into point slope form: y-y1=m(x-x1). In the point (4, 0), 4 would be x1 and 0 would be y1. so, the new equation is y-0=3/4 (x-4). now, distrubute the 3/4, leaving you with y=3/4x-3. This is correct since the slope remains the same in both equations with a different y-intercept. To check deeper, you could place point (4, 0) on a graph and then rise 3, run 4 until you get the line :) hope this helps

7 0
3 years ago
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