All categories

3 years ago

The sum of two numbers is 27. One number is 3 more than the other. Write and solve a system of equations to find the two numbers

2 answers:

7 0

X + y = 27
x = y + 3

y + 3 + y = 27
2y + 3 = 27
2y = 27 - 3
2y = 24
y = 24/2
y = 12

x = y + 3
x = 12 + 3
x = 15

ur numbers are 12 and 15

Dahasolnce [82]3 years ago

6 0

Solution:
Let, a number be x and another be x +3.
By question,
x + x +3=27
or, 2x=27-3
or, 2x = 24
or, x = 24/2
or, x = 12
Then,
One number is 12.
And, another number = 12+3= 15.
Hence,
The numbers are 12 and 15.

Hope it helped.

You might be interested in

What is the answer? I don’t understand how to get it.

miss Akunina [59]

Answer:

Step-by-step explanation:

Sub in the (x,y) points given into the equation to see if true ....you'll find A is the answer

Example point (3,95 ) 95 = -10.375 (3) + 126.125 ??

95 = 95 Check !

then try the other point ( 11,12) to be sure ....

5 0

2 years ago

Use fraction models to solve two and four sevenths plus three and two fourths equals blank

jenyasd209 [6]

Answer:

$6 \frac{1}{14}$

Step-by-step explanation:

Write down the problem;

$2 \frac{4}{7} + 3 \frac{2}{4}$

Simplify

$2 \frac{4}{7} + 3 \frac{1}{2}$

Convert so that the fractions have a common denominator; multiply the numerator and denominator of both fractions such that the denominators are equal;

$2 \frac{8}{14} + 3 \frac{7}{14}$

Add the fractions;

$5 \frac{15}{14}$

Convert to mixed number;

$6 \frac{1}{14}$

3 0

3 years ago

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

Leni [432]

Answer: $\dfrac{2x^2-1}{x(x^2-1)}$

Step-by-step explanation:

The given function : $y=\ln(x(x^2 - 1)^{\frac{1}{2}})$

$\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}$ [ $\because \ln(ab)=\ln a +\ln b$ ]

$\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}$ [ $\because \ln(a)^n=n\ln a$ ]

Now , Differentiate both sides with respect to x , we will get

$\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1)$ (By Chain rule)

[Note : $\dfrac{d}{dx}(\ln x)=\dfrac{1}{x}$ ]

$\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)$

[ $\because \dfrac{d}{dx}(x^n)=nx^{n-1}$ ]

$=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}$

Hence, the derivative of the given function is $\dfrac{2x^2-1}{x(x^2-1)}$ .

8 0

4 years ago

Andrew has a cell phone plan that provides 300 free minutes each month for

Mekhanik [1.2K]

Answer:

Andrew has a cell phone plan that provides 300 free minutes each month for a flat rate of $19. For any minutes over 300, Andrew is charged $0.39 per minute. Let x be the number of minutes Andrew uses per month and f(x) be the charges based on Andrew's cell phone plan. If then If then first 300 minutes are free and each minute of next (x-300) minutes costs $0.39, therefore Hence, { 19 + 0.39(x - 300), x > 300

Hoped I helped

4 0

3 years ago

Help me please it is literal equation

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

s = n(a + 1)

n(a + 1) = s

a + 1 = s/n

a = s/n - 1

8 0

4 years ago