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erastovalidia [21]
3 years ago
11

What is .64 divided by 3.456

Mathematics
1 answer:
Simora [160]3 years ago
6 0

the answer to this question would be 0.185185185185185

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Hello! Can someone please help me with these 2 questions! thank you so much! (i’ll give brainlist)
ra1l [238]

Answer:

1) 4    2)1/5   X=10

Step-by-step explanation:

Small to large is a fraction

Large to small is a whole number

3 0
2 years ago
I really need help on this been trying for ages
Volgvan

Answer:

cos F = adjacent/hypotenuse

= 15/28

7 0
2 years ago
A painting crew reported that a job is 3/5 completed. What fraction of the job remains to be done? ​
Debora [2.8K]

Answer:

2/5

Step-by-step explanation:

7 0
2 years ago
Find the variable h+ 1/2 = 3 1/4
Elena L [17]

Answer:

h=2 3/4

Step-by-step explanation:

2 3/4+1/2=

you can convert 1/2 into 2/4 so they have like denominators

2 3/4+2/4= 2 5/4 which is also equal to 3 1/4

7 0
3 years ago
Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0
2 years ago
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