A complex mathematical topic, the asymptotic behavior of sequences of random variables, or the behavior of indefinitely long sequences of random variables, has significant ramifications for the statistical analysis of data from large samples.
The asymptotic behavior of the sample estimators of the eigenvalues and eigenvectors of covariance matrices is examined in this claim. This work focuses on limited sample size scenarios where the number of accessible observations is comparable in magnitude to the observation dimension rather than usual high sample-size asymptotic .
Under the presumption that both the sample size and the observation dimension go to infinity while their quotient converges to a positive value, the asymptotic behavior of the conventional sample estimates is examined using methods from random matrix theory.
Closed form asymptotic expressions of these estimators are obtained, demonstrating the inconsistency of the conventional sample estimators in these asymptotic conditions, assuming that an asymptotic eigenvalue splitting condition is satisfied.
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Answer: Total number of those who took part in the survey (T)=2000
Those who were satisfied (t)=1320
Percentage of those who were satisfied (S)=(t/T)*100
S=(1320/2000)*100
S=66%
Therefore only 66% were satisfied
Step-by-step explanation:
Answer:


Step-by-step explanation:
equation (1): 
equation (2): y=2x
solve the system by substitution
step1: sub (2x) for y in equation 1:


step2: simplify the expression:


(divide by 2 for both sides)

To find the value for y sub 21/4 for x in equation 2:
y=2x
y=2×(21/4)

Answer:
H = 60(3/4)^x
Step-by-step explanation:
After each bounce, the height it reach is 3/4 the previous one.
Let the height of nth bounce be denoted as h_n and the first bounce is h_1.
We are given that h_1 = 60 cm. Following the rule in the problem, we get:
h_2 = (3/4)h_1 = (3/4)60
h_3 = (3/4)h_2 = (3/4)*(3/4)60 = 60(3/4)^2
h_4 = (3/4)h_3 = (3/4)*60(3/4)^2= 60(3/4)^3
We see that h_n = 60(3/4)^n is the formula for the height for the nth bounce. Therefore, H = 60(3/4)^x is the answer.
I hope this helps! :)