Hey there ;-)
It will be <u>-13</u>,
as the other numbers can also be there in the inner circle.
<em>By </em><em>Benjemin</em> ☺️
If your functions are
f(x) = 16·x
g(x) = 16·(1/2x)
The output values of g(x) are one-half the output values of f(x) for the same value of x.
If your functions are
f(x) = 16^x
g(x) = 16^(1/2x)
The output vaules of g(x) are the square root of the output values of f(x) for the same value of x.
_____
You seem to have left out the relevant operator symbol, so we don't really know your intent. Copy/paste operations will do that. Editing is sometimes needed.
Since triangle BDE is right, we can check it for special rules: BD is hypotenuse = 20, and BE = 12, both divisible by 4: get 5 and 3... so it's a 3-4-5 special right triangle, the 4×4 = 16 m for side DE.
Since AD bisects angle A, I think then side DG should be congruent with DG. So then
DG = 16 m
The answer is 12 ÷ 3
Step-by-step explanation:
12 ÷ 3
4
